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A company manufactures 2,000 units of its flagship product in a day. The quality control department takes a random sample of 40 units to test for quality. The product is put through a wear-and-tear test to determine the number of days it can last. If the product has a lifespan of less than 26 days, it is considered defective. The table gives the sample data that a quality control manager collected.

\begin{tabular}{|l|l|l|l|l|}
\hline 39 & 31 & 38 & 40 & 29 \\
\hline 32 & 33 & 39 & 35 & 32 \\
\hline 32 & 27 & 30 & 31 & 27 \\
\hline 30 & 29 & 34 & 36 & 25 \\
\hline 30 & 32 & 38 & 35 & 40 \\
\hline 29 & 32 & 31 & 26 & 26 \\
\hline 32 & 26 & 30 & 40 & 32 \\
\hline 39 & 37 & 25 & 29 & 34 \\
\hline
\end{tabular}

The point estimate of the population mean is [tex]$\square$[/tex].

The point estimate of the proportion of defective units is [tex]$\square$[/tex].


Sagot :

To find the point estimates, we need to calculate two things:
1. The point estimate of the population mean.
2. The point estimate of the proportion of defective units.

### Calculation of the Point Estimate of the Population Mean:
The point estimate of the population mean is the average lifespan of the sample data. The sample data provided is:

[tex]\[ 39, 31, 38, 40, 29, 32, 33, 39, 35, 32, 32, 27, 30, 31, 27, 30, 29, 34, 36, 25, 30, 32, 38, 35, 40, 29, 32, 31, 26, 26, 32, 26, 30, 40, 32, 39, 37, 25, 29, 34 \][/tex]

The point estimate of the population mean is calculated as:

[tex]\[ \text{Point estimate of the population mean} = \frac{\sum \text{sample data}}{\text{number of samples}} \][/tex]

Summing all the sample data, we get 1292. Dividing by the number of samples (40), we get:

[tex]\[ \frac{1292}{40} = 32.3 \][/tex]

### Calculation of the Point Estimate of the Proportion of Defective Units:
A product is considered defective if its lifespan is less than 26 days. We count the number of defective units in the sample data and then divide that by the total number of units in the sample.

Counting the defective units (those less than 26 days), we find that there are 2 defective units.

The point estimate of the proportion of defective units is:

[tex]\[ \text{Point estimate of the proportion of defective units} = \frac{\text{number of defective units}}{\text{total number of units}} \][/tex]

So,

[tex]\[ \frac{2}{40} = 0.05 \][/tex]

### Final Answers:
The point estimate of the population mean is [tex]\( \boxed{32.3} \)[/tex] and the point estimate of the proportion of defective units is [tex]\( \boxed{0.05} \)[/tex].