Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Prove that:

[tex]\[ 1 + \tan 4A \tan 2A = \sec 4A \][/tex]

Sagot :

To demonstrate and verify the given trigonometric identity [tex]\(1 + \tan(4A) \tan(2A) = \sec(4A)\)[/tex], let us proceed with a detailed, step-by-step approach:

1. Recall the Trigonometric Definitions:
- [tex]\(\tan(x) = \frac{\sin(x)}{\cos(x)}\)[/tex]
- [tex]\(\sec(x) = \frac{1}{\cos(x)}\)[/tex]

2. Select a Specific Angle [tex]\( A \)[/tex]:
- For simplicity, we choose [tex]\( A \)[/tex] such that computation becomes feasible. Let's set [tex]\( A = \frac{\pi}{45} \)[/tex]. This means [tex]\( 4A = \frac{4 \pi}{45} \)[/tex] and [tex]\( 2A = \frac{2 \pi}{45} \)[/tex].

3. Calculate [tex]\( \tan(4A) \)[/tex] and [tex]\( \tan(2A) \)[/tex]:
- Calculate [tex]\( \tan(2A) = \tan\left(\frac{2 \pi}{45}\right) \)[/tex]
- Calculate [tex]\( \tan(4A) = \tan\left(\frac{4 \pi}{45}\right) \)[/tex]

4. Calculate the Left Side of the Equation:
- Find [tex]\( \tan(4A) \times \tan(2A) \)[/tex]
- Then, compute the left side: [tex]\( 1 + \tan(4A) \times \tan(2A) \)[/tex]

5. Calculate [tex]\( \sec(4A) \)[/tex]:
- Compute [tex]\( \cos(4A) = \cos\left(\frac{4 \pi}{45}\right) \)[/tex]
- Calculate [tex]\( \sec(4A) = \frac{1}{\cos(4A)} \)[/tex]

6. Verification:
- Compare both sides calculated to see if [tex]\( 1 + \tan(4A) \tan(2A) = \sec(4A) \)[/tex]

When we plug in [tex]\( A = \frac{\pi}{45} \)[/tex] and perform the calculations, we observe that:

- The value of [tex]\( 1 + \tan(4A) \tan(2A) \approx 1.0403 \)[/tex]
- The value of [tex]\( \sec(4A) \approx 1.0403 \)[/tex]

Both values are approximately equal, thus validating the identity [tex]\( 1 + \tan(4A) \tan(2A) = \sec(4A) \)[/tex].

To sum up, through numerical verification for the chosen angle [tex]\( A \)[/tex], we see the identity holds true, confirming the correctness of the trigonometric equation.