Find the best solutions to your questions at Westonci.ca, the premier Q&A platform with a community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To graph the function [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex] and identify its asymptotes, we need to follow a systematic approach. Let's break it down step-by-step:
### Step 1: Identify the Vertical Asymptotes
Vertical asymptotes occur where the denominator of the function is equal to zero because the function value tends towards infinity at these points.
For [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex]:
Set the denominator equal to zero:
[tex]\[ 2x - 3 = 0 \][/tex]
Solve for [tex]\( x \)[/tex]:
[tex]\[ 2x = 3 \][/tex]
[tex]\[ x = \frac{3}{2} \][/tex]
So, there is a vertical asymptote at [tex]\( x = \frac{3}{2} \)[/tex].
### Step 2: Identify the Horizontal Asymptote
Horizontal asymptotes are identified by analyzing the behavior of the function as [tex]\( x \)[/tex] approaches positive or negative infinity.
For the function [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex]:
Consider the limit as [tex]\( x \)[/tex] approaches infinity:
[tex]\[ \lim_{x \to \infty} \frac{-4}{2x - 3} \][/tex]
As [tex]\( x \)[/tex] becomes very large, the term [tex]\( -3 \)[/tex] in the denominator becomes negligible. Thus, the function approaches:
[tex]\[ \lim_{x \to \infty} \frac{-4}{2x - 3} \approx \frac{-4}{2x} \][/tex]
[tex]\[ = \lim_{x \to \infty} \frac{-4}{2} \cdot \frac{1}{x} \][/tex]
[tex]\[ = \frac{-4}{2} \cdot 0 \][/tex]
[tex]\[ = 0 \][/tex]
So, the horizontal asymptote is at [tex]\( y = 0 \)[/tex].
### Step 3: Graph the Function
To plot the function, we follow these steps:
1. Plot the Asymptotes:
- Draw a vertical line at [tex]\( x = \frac{3}{2} \)[/tex].
- Draw a horizontal line at [tex]\( y = 0 \)[/tex].
2. Plot the Function:
- Choose several points on either side of the vertical asymptote to get the shape of the curve.
- As [tex]\( x \)[/tex] approaches the vertical asymptote from either side, the function value tends towards [tex]\( \pm \infty \)[/tex].
- As [tex]\( x \)[/tex] approaches [tex]\( \pm \infty \)[/tex], the function approaches the horizontal asymptote [tex]\( y = 0 \)[/tex].
Here is a sketch of the graph based on these observations:
### Graph of [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex]:
1. Vertical Asymptote: [tex]\( x = \frac{3}{2} \)[/tex]
2. Horizontal Asymptote: [tex]\( y = 0 \)[/tex]
[tex]\[ \begin{array}{c|c} x & q(x) \\ \hline -2 & \frac{-4}{-4 - 3} = \frac{-4}{-7} \approx 0.571 \\ 0 & \frac{-4}{-3} \approx 1.333 \\ 1 & \frac{-4}{-1} = 4 \\ \end{array} \][/tex]
As [tex]\( x \to \frac{3}{2}^- \)[/tex], [tex]\( q(x) \to -\infty \)[/tex].
As [tex]\( x \to \frac{3}{2}^+ \)[/tex], [tex]\( q(x) \to \infty \)[/tex].
### Drawing:
On a Cartesian plane, draw the vertical line [tex]\( x = \frac{3}{2} \)[/tex] and the horizontal line [tex]\( y = 0 \)[/tex]. Plot points such as [tex]\( (-2, 0.571) \)[/tex], [tex]\( (0, 1.333) \)[/tex], and [tex]\( (1, 4) \)[/tex]. Draw the curve approaching the asymptotes:
- For [tex]\( x < \frac{3}{2} \)[/tex], the curve falls from positive values approaching the vertical asymptote.
- For [tex]\( x > \frac{3}{2} \)[/tex], the curve rises from negative values approaching the vertical asymptote.
In this manner, the graph will display the behavior defined by the asymptotes and calculated points.
### Step 1: Identify the Vertical Asymptotes
Vertical asymptotes occur where the denominator of the function is equal to zero because the function value tends towards infinity at these points.
For [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex]:
Set the denominator equal to zero:
[tex]\[ 2x - 3 = 0 \][/tex]
Solve for [tex]\( x \)[/tex]:
[tex]\[ 2x = 3 \][/tex]
[tex]\[ x = \frac{3}{2} \][/tex]
So, there is a vertical asymptote at [tex]\( x = \frac{3}{2} \)[/tex].
### Step 2: Identify the Horizontal Asymptote
Horizontal asymptotes are identified by analyzing the behavior of the function as [tex]\( x \)[/tex] approaches positive or negative infinity.
For the function [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex]:
Consider the limit as [tex]\( x \)[/tex] approaches infinity:
[tex]\[ \lim_{x \to \infty} \frac{-4}{2x - 3} \][/tex]
As [tex]\( x \)[/tex] becomes very large, the term [tex]\( -3 \)[/tex] in the denominator becomes negligible. Thus, the function approaches:
[tex]\[ \lim_{x \to \infty} \frac{-4}{2x - 3} \approx \frac{-4}{2x} \][/tex]
[tex]\[ = \lim_{x \to \infty} \frac{-4}{2} \cdot \frac{1}{x} \][/tex]
[tex]\[ = \frac{-4}{2} \cdot 0 \][/tex]
[tex]\[ = 0 \][/tex]
So, the horizontal asymptote is at [tex]\( y = 0 \)[/tex].
### Step 3: Graph the Function
To plot the function, we follow these steps:
1. Plot the Asymptotes:
- Draw a vertical line at [tex]\( x = \frac{3}{2} \)[/tex].
- Draw a horizontal line at [tex]\( y = 0 \)[/tex].
2. Plot the Function:
- Choose several points on either side of the vertical asymptote to get the shape of the curve.
- As [tex]\( x \)[/tex] approaches the vertical asymptote from either side, the function value tends towards [tex]\( \pm \infty \)[/tex].
- As [tex]\( x \)[/tex] approaches [tex]\( \pm \infty \)[/tex], the function approaches the horizontal asymptote [tex]\( y = 0 \)[/tex].
Here is a sketch of the graph based on these observations:
### Graph of [tex]\( q(x) = \frac{-4}{2x - 3} \)[/tex]:
1. Vertical Asymptote: [tex]\( x = \frac{3}{2} \)[/tex]
2. Horizontal Asymptote: [tex]\( y = 0 \)[/tex]
[tex]\[ \begin{array}{c|c} x & q(x) \\ \hline -2 & \frac{-4}{-4 - 3} = \frac{-4}{-7} \approx 0.571 \\ 0 & \frac{-4}{-3} \approx 1.333 \\ 1 & \frac{-4}{-1} = 4 \\ \end{array} \][/tex]
As [tex]\( x \to \frac{3}{2}^- \)[/tex], [tex]\( q(x) \to -\infty \)[/tex].
As [tex]\( x \to \frac{3}{2}^+ \)[/tex], [tex]\( q(x) \to \infty \)[/tex].
### Drawing:
On a Cartesian plane, draw the vertical line [tex]\( x = \frac{3}{2} \)[/tex] and the horizontal line [tex]\( y = 0 \)[/tex]. Plot points such as [tex]\( (-2, 0.571) \)[/tex], [tex]\( (0, 1.333) \)[/tex], and [tex]\( (1, 4) \)[/tex]. Draw the curve approaching the asymptotes:
- For [tex]\( x < \frac{3}{2} \)[/tex], the curve falls from positive values approaching the vertical asymptote.
- For [tex]\( x > \frac{3}{2} \)[/tex], the curve rises from negative values approaching the vertical asymptote.
In this manner, the graph will display the behavior defined by the asymptotes and calculated points.
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.