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Heather's work to find the distance between two points, [tex]\( R(-3,-4) \)[/tex] and [tex]\( S(5,7) \)[/tex], is shown:
[tex]\[
\begin{aligned}
RS & =\sqrt{((-4)-(-3))^2+(7-5)^2} \\
& =\sqrt{(-1)^2+(2)^2} \\
& =\sqrt{1+4} \\
& =\sqrt{5}
\end{aligned}
\][/tex]

What error, if any, did Heather make?
A. She substituted incorrectly into the distance formula.
B. She subtracted the coordinates instead of adding them.
C. She made a sign error when simplifying inside the radical.
D. She made no errors.

Sagot :

To determine the distance between two points [tex]\( R(-3, -4) \)[/tex] and [tex]\( S(5, 7) \)[/tex], we use the distance formula:

[tex]\[ RS = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]

For points [tex]\( R(-3, -4) \)[/tex] and [tex]\( S(5, 7) \)[/tex], the coordinates are:
[tex]\( x_1 = -3\)[/tex], [tex]\( y_1 = -4\)[/tex], [tex]\( x_2 = 5 \)[/tex], and [tex]\( y_2 = 7 \)[/tex].

Substitute these coordinates into the distance formula:

[tex]\[ RS = \sqrt{(5 - (-3))^2 + (7 - (-4))^2} \][/tex]

Simplify inside the parentheses:
[tex]\[ RS = \sqrt{(5 + 3)^2 + (7 + 4)^2} \][/tex]

Further simplifying:
[tex]\[ RS = \sqrt{8^2 + 11^2} \][/tex]

Calculate the squares:
[tex]\[ RS = \sqrt{64 + 121} \][/tex]

Add the results inside the radical:
[tex]\[ RS = \sqrt{185} \][/tex]

So, the correct distance is:
[tex]\[ RS \approx 13.6 \][/tex]

Now, let's compare this with Heather's calculation. Heather's steps were:

[tex]\[ RS = \sqrt{((-4)-(-3))^2 + (7-5)^2} \][/tex]
[tex]\[ = \sqrt{(-1)^2 + (2)^2} \][/tex]
[tex]\[ = \sqrt{1 + 4} \][/tex]
[tex]\[ = \sqrt{5} \][/tex]

Heather's final result was [tex]\( \sqrt{5} \approx 2.24\)[/tex]. Upon reviewing her steps, we see that:

1. She substituted the coordinates incorrectly:
[tex]\[ ((-4)-(-3))^2 \Rightarrow (-4 + 3)^2 = (-1)^2 \][/tex]
[tex]\[ (7-5)^2 = 2^2 \][/tex]

Instead of correctly using:
[tex]\[ (5 - (-3))^2 \Rightarrow (5 + 3)^2 = 8^2 \][/tex]
[tex]\[ (7 - (-4))^2 \Rightarrow (7 + 4)^2 = 11^2 \][/tex]

This indicates that Heather substituted the coordinates incorrectly into the distance formula.

Therefore, the correct answer is:
A. She substituted incorrectly into the distance formula
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