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Sagot :
To determine the pOH of the solution given that the concentration of hydroxide ions, [tex]\([OH^-]\)[/tex], is 0.00500 M, we can follow these steps:
1. Identify the formula for pOH:
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
2. Insert the concentration of [tex]\([\text{OH}^-]\)[/tex]:
[tex]\[ [\text{OH}^-] = 0.00500\text{ M} \][/tex]
3. Calculate the pOH:
[tex]\[ \text{pOH} = -\log_{10}(0.00500) \][/tex]
Performing the logarithmic calculation:
[tex]\[ \text{pOH} = -\log_{10}(0.00500) \approx 2.30 \][/tex]
Thus, the pOH of the solution is approximately 2.30.
Therefore, the correct answer is:
[tex]\[ \boxed{2.30} \][/tex]
1. Identify the formula for pOH:
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
2. Insert the concentration of [tex]\([\text{OH}^-]\)[/tex]:
[tex]\[ [\text{OH}^-] = 0.00500\text{ M} \][/tex]
3. Calculate the pOH:
[tex]\[ \text{pOH} = -\log_{10}(0.00500) \][/tex]
Performing the logarithmic calculation:
[tex]\[ \text{pOH} = -\log_{10}(0.00500) \approx 2.30 \][/tex]
Thus, the pOH of the solution is approximately 2.30.
Therefore, the correct answer is:
[tex]\[ \boxed{2.30} \][/tex]
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