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According to the table, how much more water falls from Khone Falls compared to Horseshoe Falls in one second?

\begin{tabular}{|l|l|c|}
\hline
Waterfall & \multicolumn{1}{|c|}{City} & \begin{tabular}{c}
Volume of Water Flow \\
[tex]$\left(m^3/\text{sec}\right)$[/tex]
\end{tabular} \\
\hline
Boyoma & Congo & 17,000 \\
\hline
Khone & Laos & 11,610 \\
\hline
Horseshoe & Niagara & 5,830 \\
\hline
\end{tabular}

A. [tex]$5,780 \, m^3$[/tex]
B. [tex]$11,170 \, m^3$[/tex]
C. [tex]$5,390 \, m^3$[/tex]
D. [tex]$11,610 \, m^3$[/tex]


Sagot :

To determine how much more water falls from Khone Falls compared to Horseshoe Falls in one second, we start by looking at the volume of water falling from each waterfall as given in the table.

Here are the volumes:

- Khone Falls: [tex]\( 11,610 \, \text{m}^3/\text{sec} \)[/tex]
- Horseshoe Falls: [tex]\( 5,830 \, \text{m}^3/\text{sec} \)[/tex]

To find the difference in volume between the two waterfalls, we subtract the volume of water falling from Horseshoe Falls from the volume of water falling from Khone Falls:

[tex]\[ 11,610 \, \text{m}^3/\text{sec} - 5,830 \, \text{m}^3/\text{sec} \][/tex]

When we perform this subtraction, we get:

[tex]\[ 11,610 - 5,830 = 5,780 \, \text{m}^3/\text{sec} \][/tex]

Therefore, [tex]\( 5,780 \, \text{m}^3/\text{sec} \)[/tex] more water falls from Khone Falls compared to Horseshoe Falls in one second.

The correct answer is:

[tex]\[ \text{D) } 5,780 \, \text{m}^3 \][/tex]
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