To solve this problem, let’s find the probability that a randomly selected car is a two-door hybrid using the given data.
1. Identify the total number of two-door hybrid cars:
- From the table, the number of two-door hybrid cars is [tex]\( 14 \)[/tex].
2. Identify the total number of cars:
- The total number of cars is the sum of all the frequencies in the table. Adding these, we get:
[tex]\[
19 (\text{two-door} \text{ + both hybrid and not hybrid}) + 28 (\text{four-door} \text{ + both hybrid and not hybrid}) = 47
\][/tex]
3. Calculate the probability:
- The probability that a randomly selected car is a two-door hybrid is found by dividing the number of two-door hybrid cars by the total number of cars:
[tex]\[
\frac{14}{47}
\][/tex]
4. Convert the probability to a percentage:
- To convert the fraction to a percentage, we multiply by 100:
[tex]\[
\left( \frac{14}{47} \right) \times 100 \approx 29.78723404255319 \%
\][/tex]
5. Round the result to the nearest tenth percent:
- To round 29.78723404255319 to the nearest tenth, we look at the second digit after the decimal point. Since it is 8, we round up:
[tex]\[
\approx 29.8\%
\][/tex]
Thus, the probability that a randomly selected car is a two-door hybrid, expressed as a percentage rounded to the nearest tenth of a percent, is [tex]\( \boxed{29.8\%} \)[/tex].
