Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To find out which equation represents a circle that contains the point [tex]$(-2, 8)$[/tex] and has a center at [tex]$(4, 0)$[/tex], we need to determine the radius of the circle first and then see which of the given equations matches this information.
### Step 1: Calculate the radius
The radius [tex]\( r \)[/tex] of the circle can be found using the distance formula between the point [tex]$(-2, 8)$[/tex] and the center of the circle [tex]$(4, 0)$[/tex].
The distance formula is:
[tex]\[ r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the given points [tex]$(x_1, y_1) = (-2, 8)$[/tex] and [tex]$(x_2, y_2) = (4, 0)$[/tex],
[tex]\[ r = \sqrt{(4 - (-2))^2 + (0 - 8)^2} = \sqrt{(4 + 2)^2 + (-8)^2} = \sqrt{6^2 + (-8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \][/tex]
So, the radius [tex]\( r \)[/tex] is [tex]$10$[/tex].
### Step 2: Write the equation of the circle
The standard form of the equation of a circle with center [tex]$(h, k)$[/tex] and radius [tex]$r$[/tex] is:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Substituting [tex]\( h = 4 \)[/tex], [tex]\( k = 0 \)[/tex], and [tex]\( r = 10 \)[/tex],
[tex]\[ (x - 4)^2 + y^2 = 10^2 = 100 \][/tex]
### Step 3: Verify which given equation matches
From the options provided, we need to identify which equation matches the calculated circle's equation.
1. [tex]$(x - 4)^2 + y^2 = 100$[/tex]
2. [tex]$(x - 4)^2 + y^2 = 10$[/tex]
3. [tex]$x^2 + (y - 4)^2 = 10$[/tex]
4. [tex]$x^2 + (y - 4)^2 = 100$[/tex]
The equation of the circle derived above is:
[tex]\[ (x - 4)^2 + y^2 = 100 \][/tex]
Comparing this with the given options, the first option [tex]$(x - 4)^2 + y^2 = 100$[/tex] matches perfectly.
### Conclusion
The equation that represents a circle containing the point [tex]$(-2, 8)$[/tex] and having a center at [tex]$(4, 0)$[/tex] is:
[tex]\[ (x - 4)^2 + y^2 = 100 \][/tex]
### Step 1: Calculate the radius
The radius [tex]\( r \)[/tex] of the circle can be found using the distance formula between the point [tex]$(-2, 8)$[/tex] and the center of the circle [tex]$(4, 0)$[/tex].
The distance formula is:
[tex]\[ r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Substituting the given points [tex]$(x_1, y_1) = (-2, 8)$[/tex] and [tex]$(x_2, y_2) = (4, 0)$[/tex],
[tex]\[ r = \sqrt{(4 - (-2))^2 + (0 - 8)^2} = \sqrt{(4 + 2)^2 + (-8)^2} = \sqrt{6^2 + (-8)^2} = \sqrt{36 + 64} = \sqrt{100} = 10 \][/tex]
So, the radius [tex]\( r \)[/tex] is [tex]$10$[/tex].
### Step 2: Write the equation of the circle
The standard form of the equation of a circle with center [tex]$(h, k)$[/tex] and radius [tex]$r$[/tex] is:
[tex]\[ (x - h)^2 + (y - k)^2 = r^2 \][/tex]
Substituting [tex]\( h = 4 \)[/tex], [tex]\( k = 0 \)[/tex], and [tex]\( r = 10 \)[/tex],
[tex]\[ (x - 4)^2 + y^2 = 10^2 = 100 \][/tex]
### Step 3: Verify which given equation matches
From the options provided, we need to identify which equation matches the calculated circle's equation.
1. [tex]$(x - 4)^2 + y^2 = 100$[/tex]
2. [tex]$(x - 4)^2 + y^2 = 10$[/tex]
3. [tex]$x^2 + (y - 4)^2 = 10$[/tex]
4. [tex]$x^2 + (y - 4)^2 = 100$[/tex]
The equation of the circle derived above is:
[tex]\[ (x - 4)^2 + y^2 = 100 \][/tex]
Comparing this with the given options, the first option [tex]$(x - 4)^2 + y^2 = 100$[/tex] matches perfectly.
### Conclusion
The equation that represents a circle containing the point [tex]$(-2, 8)$[/tex] and having a center at [tex]$(4, 0)$[/tex] is:
[tex]\[ (x - 4)^2 + y^2 = 100 \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.