Sure! Let's go step-by-step to find out how much more hydrochloric acid Cameron used in the second experiment compared to the first experiment.
1. Convert the mixed numbers to improper fractions (or decimals):
- For the first experiment, Cameron used [tex]\(1 \frac{3}{4}\)[/tex] ounces. Converting this to a decimal:
[tex]\[
1 + \frac{3}{4} = 1 + 0.75 = 1.75 \, \text{ounces}
\][/tex]
- For the second experiment, Cameron used [tex]\(2 \frac{3}{8}\)[/tex] ounces. Converting this to a decimal:
[tex]\[
2 + \frac{3}{8} = 2 + 0.375 = 2.375 \, \text{ounces}
\][/tex]
2. Determine the difference between the amounts used in the two experiments:
- Subtract the amount used in the first experiment from the amount used in the second experiment:
[tex]\[
2.375 - 1.75 = 0.625 \, \text{ounces}
\][/tex]
3. Identify the corresponding answer from the given choices:
- We have calculated that Cameron used [tex]\(0.625\)[/tex] ounces more in the second experiment. Now, we need to match this with the choices provided:
[tex]\[
0.625 = \frac{5}{8} \, \text{ounce}
\][/tex]
4. Choices given:
- [tex]\(1 \frac{5}{8}\)[/tex] ounces
- [tex]\(4 \frac{1}{8}\)[/tex] ounces
- [tex]\(\frac{5}{8}\)[/tex] ounce
- [tex]\(\frac{3}{8}\)[/tex] ounce
From the calculation, we see that [tex]\(0.625\)[/tex] (or [tex]\(\frac{5}{8}\)[/tex]) ounce corresponds to the third choice.
Therefore, Cameron used [tex]\(\frac{5}{8}\)[/tex] ounce more hydrochloric acid in the second experiment compared to the first experiment.
