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Exercise 13.5

1. A man deposited an amount of money in his savings account for 5 years. The rate of interest was [tex]14\%[/tex] per annum. If the interest was [tex]GH \$3500.00[/tex], find the amount deposited.


Sagot :

To determine the amount of money that a man deposited in his savings account, given the time period and interest rate, we can use the simple interest formula. Here's a step-by-step breakdown of the solution:

1. Identify the given information:
- Time period (T): 5 years
- Annual interest rate (R): 14%
- Interest earned (I): GH₵ 3500.00

2. Convert the annual interest rate from percentage to decimal:
- 14% as a decimal is 0.14 (since 14% = 14/100 = 0.14).

3. Simple Interest Formula:
- The formula for simple interest is:
[tex]\[ \text{Interest} = \text{Principal} \times \text{Rate} \times \text{Time} \][/tex]
- Rearrange this formula to solve for the principal (P):
[tex]\[ \text{Principal} = \frac{\text{Interest}}{\text{Rate} \times \text{Time}} \][/tex]

4. Substitute the given values into the formula:
- Interest (I) = GH₵ 3500.00
- Rate (R) = 0.14
- Time (T) = 5 years

So we have:
[tex]\[ \text{Principal} = \frac{3500.00}{0.14 \times 5} \][/tex]

5. Calculate the denominator:
- Multiply the rate by the time:
[tex]\[ 0.14 \times 5 = 0.70 \][/tex]

6. Divide the interest by the result:
- Now, divide the interest by this product to find the principal:
[tex]\[ \text{Principal} = \frac{3500.00}{0.70} = 5000.00 \][/tex]

7. Conclusion:
- Therefore, the amount deposited by the man was GH₵ 5000.00

So, the man deposited an amount of GH₵ 5000.00 in his savings account.