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In the cross [tex][tex]$BB \times bb$[/tex][/tex], the percentage of offspring in the [tex][tex]$F_1$[/tex][/tex] generation that will have the same genotype as one of their parents is:

A. [tex]50 \%[/tex]
B. [tex]25 \%[/tex]
C. [tex]100 \%[/tex]
D. [tex]0 \%[/tex]


Sagot :

To determine the percent of offspring in the F1 generation that will have the same genotype as one of their parents in the cross [tex]\( BB \times bb \)[/tex], let's go through the steps involved in this genetic cross.

1. Identify the parent genotypes:
- One parent is homozygous dominant [tex]\( BB \)[/tex].
- The other parent is homozygous recessive [tex]\( bb \)[/tex].

2. Determine the possible gametes:
- The [tex]\( BB \)[/tex] parent can only produce [tex]\( B \)[/tex] gametes.
- The [tex]\( bb \)[/tex] parent can only produce [tex]\( b \)[/tex] gametes.

3. Perform the cross:
- Each offspring will receive one [tex]\( B \)[/tex] allele from the [tex]\( BB \)[/tex] parent and one [tex]\( b \)[/tex] allele from the [tex]\( bb \)[/tex] parent.

4. Predict the offspring genotypes:
- All offspring in the F1 generation will have the [tex]\( Bb \)[/tex] genotype (heterozygous).

5. Compare the offspring genotypes with the parent genotypes:
- The [tex]\( Bb \)[/tex] genotype is different from both the [tex]\( BB \)[/tex] genotype and the [tex]\( bb \)[/tex] genotype.

6. Calculate the percent of offspring with the same genotype as their parents:
- Since none of the offspring have the [tex]\( BB \)[/tex] or [tex]\( bb \)[/tex] genotype, [tex]\( 0\% \)[/tex] of the offspring have the same genotype as either of the parents.

Therefore, the percent of offspring in the F1 generation that have the same genotype as one of their parents is [tex]\( 0 \% \)[/tex]. The correct answer is:

[tex]\[ \boxed{0\%} \][/tex]