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A bag contains 3 red, 2 yellow, and 3 green marbles. You reach in and draw out three marbles without replacement.

What is the probability that the first two marbles will be green and the third will be yellow?

Sagot :

Sure, let's break this problem down step-by-step.

### Step 1: Determine the Total Number of Marbles

First, we need to understand the composition of the marbles in the bag:
- Red marbles: 3
- Yellow marbles: 2
- Green marbles: 3

So, the total number of marbles in the bag is:
[tex]\[ 3 + 2 + 3 = 8 \][/tex]

### Step 2: Probability of Drawing the First Green Marble

To find the probability of drawing a green marble first, we look at the number of green marbles and the total marbles:
[tex]\[ \text{Probability of drawing first green marble} = \frac{\text{Number of green marbles}}{\text{Total number of marbles}} = \frac{3}{8} = 0.375 \][/tex]

### Step 3: Probability of Drawing the Second Green Marble

After drawing one green marble, there are now 2 green marbles left and a total of 7 marbles remaining in the bag.
[tex]\[ \text{Probability of drawing second green marble} = \frac{\text{Remaining green marbles}}{\text{Remaining total marbles}} = \frac{2}{7} \approx 0.2857 \][/tex]

### Step 4: Probability of Drawing a Yellow Marble on the Third Draw

After drawing two green marbles, there are 2 yellow marbles left and a total of 6 marbles remaining in the bag.
[tex]\[ \text{Probability of drawing third yellow marble} = \frac{\text{Remaining yellow marbles}}{\text{Remaining total marbles}} = \frac{2}{6} = \frac{1}{3} \approx 0.3333 \][/tex]

### Step 5: Combining the Probabilities

The events are sequential and without replacement, so the overall probability is the product of the individual probabilities:
[tex]\[ \text{Overall Probability} = \left( \frac{3}{8} \right) \times \left( \frac{2}{7} \right) \times \left( \frac{1}{3} \right) \][/tex]

### Final Computation

[tex]\[ \text{Overall Probability} = 0.375 \times 0.2857 \times 0.3333 \approx 0.0357 \][/tex]

Hence, the probability that the first two marbles drawn are green and the third marble drawn is yellow is approximately:
[tex]\[ 0.0357 \][/tex]

So there you have it! This is a step-by-step solution showing how to find the probability that the first two marbles drawn are green and the third is yellow, which is approximately [tex]\(0.0357\)[/tex].