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Sagot :
To solve the repeated addition of vectors step-by-step, let's add each vector component-wise.
Given the vectors:
[tex]\[ \begin{pmatrix} 1 \\ 3 \end{pmatrix}, \begin{pmatrix} 1 \\ 3 \end{pmatrix}, \begin{pmatrix} 1 \\ 3 \end{pmatrix} \][/tex]
We need to calculate the sum for each component separately:
1. First component (a):
[tex]\[ a = 1 + 1 + 1 \][/tex]
2. Second component (b):
[tex]\[ b = 3 + 3 + 3 \][/tex]
Calculating each:
- For the first component (a):
[tex]\[ 1 + 1 + 1 = 3 \][/tex]
- For the second component (b):
[tex]\[ 3 + 3 + 3 = 9 \][/tex]
So, the resulting vector from the addition is:
[tex]\[ \begin{pmatrix} 3 \\ 9 \end{pmatrix} \][/tex]
Thus, [tex]\( a = 3 \)[/tex] and [tex]\( b = 9 \)[/tex].
Given the vectors:
[tex]\[ \begin{pmatrix} 1 \\ 3 \end{pmatrix}, \begin{pmatrix} 1 \\ 3 \end{pmatrix}, \begin{pmatrix} 1 \\ 3 \end{pmatrix} \][/tex]
We need to calculate the sum for each component separately:
1. First component (a):
[tex]\[ a = 1 + 1 + 1 \][/tex]
2. Second component (b):
[tex]\[ b = 3 + 3 + 3 \][/tex]
Calculating each:
- For the first component (a):
[tex]\[ 1 + 1 + 1 = 3 \][/tex]
- For the second component (b):
[tex]\[ 3 + 3 + 3 = 9 \][/tex]
So, the resulting vector from the addition is:
[tex]\[ \begin{pmatrix} 3 \\ 9 \end{pmatrix} \][/tex]
Thus, [tex]\( a = 3 \)[/tex] and [tex]\( b = 9 \)[/tex].
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