Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Repeated addition:
[tex]\[
\begin{array}{l}
\left[\begin{array}{l}
1 \\
3
\end{array}\right]+\left[\begin{array}{l}
1 \\
3
\end{array}\right]+\left[\begin{array}{l}
1 \\
3
\end{array}\right]=\left[\begin{array}{l}
a \\
b
\end{array}\right] \\
a=\square \quad b=\square
\end{array}
\][/tex]

Sagot :

GinnyAnswer
To solve the repeated addition of vectors step-by-step, let's add each vector component-wise.

Given the vectors:
[tex]\[ \begin{pmatrix} 1 \\ 3 \end{pmatrix}, \begin{pmatrix} 1 \\ 3 \end{pmatrix}, \begin{pmatrix} 1 \\ 3 \end{pmatrix} \][/tex]

We need to calculate the sum for each component separately:

1. First component (a):
[tex]\[ a = 1 + 1 + 1 \][/tex]

2. Second component (b):
[tex]\[ b = 3 + 3 + 3 \][/tex]

Calculating each:

- For the first component (a):
[tex]\[ 1 + 1 + 1 = 3 \][/tex]

- For the second component (b):
[tex]\[ 3 + 3 + 3 = 9 \][/tex]

So, the resulting vector from the addition is:
[tex]\[ \begin{pmatrix} 3 \\ 9 \end{pmatrix} \][/tex]

Thus, [tex]\( a = 3 \)[/tex] and [tex]\( b = 9 \)[/tex].
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.