Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
To find a polynomial function of the lowest degree with rational coefficients that has the given numbers as some of its zeros, we proceed as follows:
1. Identify the given zeros and their conjugates:
- The given zeros are [tex]\(3 - i\)[/tex] and [tex]\(\sqrt{6}\)[/tex].
- Since the polynomial must have rational coefficients, the complex zero [tex]\(3 - i\)[/tex] must be paired with its conjugate [tex]\(3 + i\)[/tex].
- Similarly, the irrational zero [tex]\(\sqrt{6}\)[/tex] must be paired with its conjugate [tex]\(-\sqrt{6}\)[/tex].
2. Form factors of the polynomial:
- For each pair of zeros, we form a factor of the polynomial. The factors corresponding to the given zeros and their conjugates are:
[tex]\[ (x - (3 - i))(x - (3 + i)) \][/tex]
[tex]\[ (x - \sqrt{6})(x + \sqrt{6}) \][/tex]
3. Expand the factors:
- First, we expand the factor for the complex conjugate zeros:
[tex]\[ (x - (3 - i))(x - (3 + i)) = (x - 3 + i)(x - 3 - i) \][/tex]
[tex]\[ = ((x - 3) + i)((x - 3) - i) \][/tex]
[tex]\[ = (x - 3)^2 - i^2 \][/tex]
Since [tex]\(i^2 = -1\)[/tex]:
[tex]\[ = (x - 3)^2 - (-1) \][/tex]
[tex]\[ = (x - 3)^2 + 1 \][/tex]
[tex]\[ = x^2 - 6x + 9 + 1 \][/tex]
[tex]\[ = x^2 - 6x + 10 \][/tex]
- Next, we expand the factor for the irrational conjugate zeros:
[tex]\[ (x - \sqrt{6})(x + \sqrt{6}) \][/tex]
[tex]\[ = x^2 - (\sqrt{6})^2 \][/tex]
[tex]\[ = x^2 - 6 \][/tex]
4. Form the polynomial by multiplying the factors:
- Now, to get the polynomial function, we need to multiply the expanded factors together:
[tex]\[ f(x) = (x^2 - 6x + 10)(x^2 - 6) \][/tex]
5. Expand the resulting polynomial:
[tex]\[ f(x) = (x^2 - 6x + 10)(x^2 - 6) \][/tex]
We distribute each term of the first polynomial to each term of the second polynomial:
[tex]\[ = x^2(x^2 - 6) - 6x(x^2 - 6) + 10(x^2 - 6) \][/tex]
[tex]\[ = (x^4 - 6x^2) - (6x^3 - 36x) + (10x^2 - 60) \][/tex]
[tex]\[ = x^4 - 6x^2 - 6x^3 + 36x + 10x^2 - 60 \][/tex]
6. Combine like terms:
[tex]\[ = x^4 - 6x^3 + 4x^2 + 36x - 60 \][/tex]
Therefore, the polynomial function in expanded form is:
[tex]\[ f(x) = x^4 - 6x^3 + 4x^2 + 36x - 60. \][/tex]
1. Identify the given zeros and their conjugates:
- The given zeros are [tex]\(3 - i\)[/tex] and [tex]\(\sqrt{6}\)[/tex].
- Since the polynomial must have rational coefficients, the complex zero [tex]\(3 - i\)[/tex] must be paired with its conjugate [tex]\(3 + i\)[/tex].
- Similarly, the irrational zero [tex]\(\sqrt{6}\)[/tex] must be paired with its conjugate [tex]\(-\sqrt{6}\)[/tex].
2. Form factors of the polynomial:
- For each pair of zeros, we form a factor of the polynomial. The factors corresponding to the given zeros and their conjugates are:
[tex]\[ (x - (3 - i))(x - (3 + i)) \][/tex]
[tex]\[ (x - \sqrt{6})(x + \sqrt{6}) \][/tex]
3. Expand the factors:
- First, we expand the factor for the complex conjugate zeros:
[tex]\[ (x - (3 - i))(x - (3 + i)) = (x - 3 + i)(x - 3 - i) \][/tex]
[tex]\[ = ((x - 3) + i)((x - 3) - i) \][/tex]
[tex]\[ = (x - 3)^2 - i^2 \][/tex]
Since [tex]\(i^2 = -1\)[/tex]:
[tex]\[ = (x - 3)^2 - (-1) \][/tex]
[tex]\[ = (x - 3)^2 + 1 \][/tex]
[tex]\[ = x^2 - 6x + 9 + 1 \][/tex]
[tex]\[ = x^2 - 6x + 10 \][/tex]
- Next, we expand the factor for the irrational conjugate zeros:
[tex]\[ (x - \sqrt{6})(x + \sqrt{6}) \][/tex]
[tex]\[ = x^2 - (\sqrt{6})^2 \][/tex]
[tex]\[ = x^2 - 6 \][/tex]
4. Form the polynomial by multiplying the factors:
- Now, to get the polynomial function, we need to multiply the expanded factors together:
[tex]\[ f(x) = (x^2 - 6x + 10)(x^2 - 6) \][/tex]
5. Expand the resulting polynomial:
[tex]\[ f(x) = (x^2 - 6x + 10)(x^2 - 6) \][/tex]
We distribute each term of the first polynomial to each term of the second polynomial:
[tex]\[ = x^2(x^2 - 6) - 6x(x^2 - 6) + 10(x^2 - 6) \][/tex]
[tex]\[ = (x^4 - 6x^2) - (6x^3 - 36x) + (10x^2 - 60) \][/tex]
[tex]\[ = x^4 - 6x^2 - 6x^3 + 36x + 10x^2 - 60 \][/tex]
6. Combine like terms:
[tex]\[ = x^4 - 6x^3 + 4x^2 + 36x - 60 \][/tex]
Therefore, the polynomial function in expanded form is:
[tex]\[ f(x) = x^4 - 6x^3 + 4x^2 + 36x - 60. \][/tex]
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.