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Yenifer is simplifying the following problem. What part(s) of her answer are incorrect? [tex]\left(\frac{4 x^{-2} y^2}{2 x^2 y^7}\right)^3 = \frac{8}{x y^3}[/tex]

A. I. The coefficient
B. II. The x exponent
C. III. The y exponent
D. I and II
E. III only
F. II only
G. II and III

Sagot :

Let's carefully analyze Yenifer's steps to simplify the given expression and identify which parts of her answer are incorrect.

### Step-by-Step Simplification:

1. Original Problem:
[tex]\[ \left(\frac{4 x^{-2} y^2}{2 x^2 y^7}\right)^3 \][/tex]

2. Simplify Inside the Parentheses:
[tex]\[ \frac{4 x^{-2} y^2}{2 x^2 y^7} \][/tex]
- Coefficient: [tex]\(\frac{4}{2} = 2\)[/tex]
- [tex]\(x\)[/tex] term: [tex]\(x^{-2} \cdot x^{-2} = x^{-4}\)[/tex]
- [tex]\(y\)[/tex] term: [tex]\(y^2 \cdot y^{-7} = y^{-5}\)[/tex]

So, the expression simplifies to:
[tex]\[ 2 x^{-4} y^{-5} \][/tex]

3. Raise Each Term to the Power of 3:
[tex]\[ (2 x^{-4} y^{-5})^3 \][/tex]
- Coefficient: [tex]\(2^3 = 8\)[/tex]
- [tex]\(x\)[/tex] term: [tex]\((x^{-4})^3 = x^{-12}\)[/tex]
- [tex]\(y\)[/tex] term: [tex]\((y^{-5})^3 = y^{-15}\)[/tex]

Thus, the expression becomes:
[tex]\[ 8 x^{-12} y^{-15} \][/tex]

4. Write the expression in the correct format (with positive exponents):
[tex]\[ 8 \cdot \frac{1}{x^{12} y^{15}} = \frac{8}{x^{12} y^{15}} \][/tex]

5. Compare with Yenifer's Answer:
Yenifer's simplified result is:
[tex]\[ \frac{8}{x y^3} \][/tex]

By comparing each part of Yenifer's answer with the correctly simplified result:
- Coefficient: Both results have the coefficient 8, which is correct.
- [tex]\(x\)[/tex] Exponent: Yenifer's answer has [tex]\(x^1\)[/tex] (or simply x) in the denominator, while the correct exponent should be [tex]\(x^{12}\)[/tex].
- [tex]\(y\)[/tex] Exponent: Yenifer's answer has [tex]\(y^3\)[/tex] in the denominator, while the correct exponent should be [tex]\(y^{15}\)[/tex].

### Incorrect Parts:
- The x exponent in Yenifer's answer is incorrect.
- The y exponent in Yenifer's answer is incorrect.

### Conclusion:
Therefore, the parts of Yenifer's answer that are incorrect are:
- II. The x exponent
- III. The y exponent

Thus, the correct answer is:
[tex]\[ \boxed{\text{II and III}} \][/tex]