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What is the pre-image of vertex [tex]A'[/tex] if the rule that created the image is [tex]r_{.}(x, y) = (-x, y)[/tex]?

A. [tex]A(-4, 2)[/tex]

B. [tex]A(-2, -4)[/tex]

C. [tex]A(2, 4)[/tex]

D. [tex]A(4, -2)[/tex]


Sagot :

To determine the pre-image of vertex [tex]\( A' \)[/tex] under the rule [tex]\( r_{\cdot}(x, y) \rightarrow (-x, y) \)[/tex], we need to reverse this transformation. The rule given changes the sign of the x-coordinate while leaving the y-coordinate unchanged.

Given the image [tex]\( A'(4, -2) \)[/tex], we need to find the original coordinates (pre-image) that would map to [tex]\( A'(4, -2) \)[/tex] using the given transformation rule [tex]\( r_{\cdot}(x, y) \rightarrow (-x, y) \)[/tex].

### Step-by-Step Solution

1. The transformation rule is [tex]\( r_{\cdot}(x, y) \rightarrow (-x, y) \)[/tex]. This means that:
- The x-coordinate of the image is the negative of the x-coordinate of the pre-image.
- The y-coordinate of the image is the same as the y-coordinate of the pre-image.

2. To find the pre-image, we need to reverse the transformation:
- If the image has coordinates [tex]\( (4, -2) \)[/tex], then the rule [tex]\( r_{\cdot}(x, y) \rightarrow (-x, y) \)[/tex] implies that:
- The x-coordinate of the pre-image should be the negative of the x-coordinate of the image. Therefore, if the image's x-coordinate is 4, the pre-image's x-coordinate should be:
[tex]\[ x = -4 \][/tex]
- The y-coordinate of the pre-image should be the same as the y-coordinate of the image. Therefore, if the image's y-coordinate is -2, the pre-image's y-coordinate should be:
[tex]\[ y = -2 \][/tex]

3. Combining these results, the pre-image coordinates before transformation would be:
[tex]\[ A(-4, -2) \][/tex]

Thus, the correct pre-image of [tex]\( A' \)[/tex] under the given rule [tex]\( r_{\cdot}(x, y) \rightarrow (-x, y) \)[/tex] is [tex]\( A(-4, -2) \)[/tex].

### Conclusion

The pre-image of vertex [tex]\( A' \)[/tex] is [tex]\( \boxed{A(-4, -2)} \)[/tex].