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What are the coordinates of the point that are [tex]\frac{1}{5}[/tex] of the way from [tex]A(-7, -4)[/tex] to [tex]B(3, 6)[/tex]?

A. [tex](-5, 0)[/tex]

B. [tex](-5, -2)[/tex]

C. [tex](1, 4)[/tex]

D. [tex](0, 3)[/tex]

Sagot :

To find the coordinates of the point that is [tex]\(\frac{1}{5}\)[/tex] of the way from [tex]\(A(-7, -4)\)[/tex] to [tex]\(B(3, 6)\)[/tex], we need to determine the difference in the [tex]\(x\)[/tex]-coordinates and the [tex]\(y\)[/tex]-coordinates between points [tex]\(A\)[/tex] and [tex]\(B\)[/tex], then scale these differences by [tex]\(\frac{1}{5}\)[/tex], and finally add these scaled differences to the coordinates of point [tex]\(A\)[/tex].

Here's the step-by-step solution:

1. Calculate the difference in the [tex]\(x\)[/tex]-coordinates:
[tex]\[ \Delta x = B_x - A_x = 3 - (-7) = 10 \][/tex]

2. Calculate the difference in the [tex]\(y\)[/tex]-coordinates:
[tex]\[ \Delta y = B_y - A_y = 6 - (-4) = 10 \][/tex]

3. Scale the differences by [tex]\(\frac{1}{5}\)[/tex]:
[tex]\[ \text{Scale in } x \text{-direction} = \frac{1}{5} \times \Delta x = \frac{1}{5} \times 10 = 2 \][/tex]
[tex]\[ \text{Scale in } y \text{-direction} = \frac{1}{5} \times \Delta y = \frac{1}{5} \times 10 = 2 \][/tex]

4. Add the scaled differences to the coordinates of point [tex]\(A\)[/tex]:
[tex]\[ \text{New } x \text{-coordinate} = A_x + \text{Scale in } x \text{-direction} = -7 + 2 = -5 \][/tex]
[tex]\[ \text{New } y \text{-coordinate} = A_y + \text{Scale in } y \text{-direction} = -4 + 2 = -2 \][/tex]

Thus, the coordinates of the point that is [tex]\(\frac{1}{5}\)[/tex] of the way from [tex]\(A(-7,\ -4)\)[/tex] to [tex]\(B(3,\ 6)\)[/tex] are [tex]\((-5, -2)\)[/tex].

The correct answer is:
[tex]\[ \boxed{(-5, -2)} \][/tex]