Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
To find the total normal force acting on the cart, we need to consider both the gravitational force and the vertical component of the applied force. Here’s a step-by-step solution:
1. Determine the mass of the cart:
The mass [tex]\( m \)[/tex] of the cart is given as [tex]\( 7.32 \)[/tex] kg.
2. Identify the force applied and its angle:
The force [tex]\( F \)[/tex] applied by the shopper is [tex]\( 14.7 \)[/tex] N, directed at [tex]\( -32.7^\circ \)[/tex] below the horizontal.
3. Calculate the gravitational force acting downward:
The gravitational force [tex]\( F_g \)[/tex] can be calculated using the relation:
[tex]\[ F_g = m \times g \][/tex]
where [tex]\( g \)[/tex] is the acceleration due to gravity ([tex]\( 9.81 \ \text{m/s}^2 \)[/tex]):
[tex]\[ F_g = 7.32 \ \text{kg} \times 9.81 \ \text{m/s}^2 = 71.8092 \ \text{N} \][/tex]
4. Determine the vertical component of the applied force:
Since the force is applied at an angle below the horizontal, we need the vertical component [tex]\( F_v \)[/tex]. The vertical component can be found using the sine of the angle [tex]\( \theta \)[/tex]:
[tex]\[ F_v = F \times \sin(\theta) \][/tex]
where [tex]\( \theta = -32.7^\circ \)[/tex]. Converting this angle to radians:
[tex]\[ \theta_{\text{rad}} = -32.7^\circ \times \frac{\pi}{180} = -0.5707226654021458 \ \text{radians} \][/tex]
Now, calculate the vertical component:
[tex]\[ F_v = 14.7 \ \text{N} \times \sin(-0.5707226654021458) = 14.7 \ \text{N} \times (-0.5707226654021458) = -7.941532711021528 \ \text{N} \][/tex]
5. Calculate the total normal force:
The normal force [tex]\( n \)[/tex] is the sum of the gravitational force and the vertical component of the applied force:
[tex]\[ n = F_g + F_v \][/tex]
Substituting the values:
[tex]\[ n = 71.8092 \ \text{N} + (-7.941532711021528 \ \text{N}) = 63.867667288978474 \ \text{N} \][/tex]
Thus, the total normal force acting on the cart is:
[tex]\[ n = 63.867667288978474 \ \text{N} \][/tex]
1. Determine the mass of the cart:
The mass [tex]\( m \)[/tex] of the cart is given as [tex]\( 7.32 \)[/tex] kg.
2. Identify the force applied and its angle:
The force [tex]\( F \)[/tex] applied by the shopper is [tex]\( 14.7 \)[/tex] N, directed at [tex]\( -32.7^\circ \)[/tex] below the horizontal.
3. Calculate the gravitational force acting downward:
The gravitational force [tex]\( F_g \)[/tex] can be calculated using the relation:
[tex]\[ F_g = m \times g \][/tex]
where [tex]\( g \)[/tex] is the acceleration due to gravity ([tex]\( 9.81 \ \text{m/s}^2 \)[/tex]):
[tex]\[ F_g = 7.32 \ \text{kg} \times 9.81 \ \text{m/s}^2 = 71.8092 \ \text{N} \][/tex]
4. Determine the vertical component of the applied force:
Since the force is applied at an angle below the horizontal, we need the vertical component [tex]\( F_v \)[/tex]. The vertical component can be found using the sine of the angle [tex]\( \theta \)[/tex]:
[tex]\[ F_v = F \times \sin(\theta) \][/tex]
where [tex]\( \theta = -32.7^\circ \)[/tex]. Converting this angle to radians:
[tex]\[ \theta_{\text{rad}} = -32.7^\circ \times \frac{\pi}{180} = -0.5707226654021458 \ \text{radians} \][/tex]
Now, calculate the vertical component:
[tex]\[ F_v = 14.7 \ \text{N} \times \sin(-0.5707226654021458) = 14.7 \ \text{N} \times (-0.5707226654021458) = -7.941532711021528 \ \text{N} \][/tex]
5. Calculate the total normal force:
The normal force [tex]\( n \)[/tex] is the sum of the gravitational force and the vertical component of the applied force:
[tex]\[ n = F_g + F_v \][/tex]
Substituting the values:
[tex]\[ n = 71.8092 \ \text{N} + (-7.941532711021528 \ \text{N}) = 63.867667288978474 \ \text{N} \][/tex]
Thus, the total normal force acting on the cart is:
[tex]\[ n = 63.867667288978474 \ \text{N} \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.