Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A shopper pushes a 7.32 kg grocery cart with a [tex][tex]$14.7 N$[/tex][/tex] force directed at [tex]-32.7^{\circ}[/tex] below the horizontal.

What is the total normal force acting upon the cart?

[tex]n = [?] N[/tex]


Sagot :

To find the total normal force acting on the cart, we need to consider both the gravitational force and the vertical component of the applied force. Here’s a step-by-step solution:

1. Determine the mass of the cart:
The mass [tex]\( m \)[/tex] of the cart is given as [tex]\( 7.32 \)[/tex] kg.

2. Identify the force applied and its angle:
The force [tex]\( F \)[/tex] applied by the shopper is [tex]\( 14.7 \)[/tex] N, directed at [tex]\( -32.7^\circ \)[/tex] below the horizontal.

3. Calculate the gravitational force acting downward:
The gravitational force [tex]\( F_g \)[/tex] can be calculated using the relation:
[tex]\[ F_g = m \times g \][/tex]
where [tex]\( g \)[/tex] is the acceleration due to gravity ([tex]\( 9.81 \ \text{m/s}^2 \)[/tex]):
[tex]\[ F_g = 7.32 \ \text{kg} \times 9.81 \ \text{m/s}^2 = 71.8092 \ \text{N} \][/tex]

4. Determine the vertical component of the applied force:
Since the force is applied at an angle below the horizontal, we need the vertical component [tex]\( F_v \)[/tex]. The vertical component can be found using the sine of the angle [tex]\( \theta \)[/tex]:
[tex]\[ F_v = F \times \sin(\theta) \][/tex]
where [tex]\( \theta = -32.7^\circ \)[/tex]. Converting this angle to radians:
[tex]\[ \theta_{\text{rad}} = -32.7^\circ \times \frac{\pi}{180} = -0.5707226654021458 \ \text{radians} \][/tex]
Now, calculate the vertical component:
[tex]\[ F_v = 14.7 \ \text{N} \times \sin(-0.5707226654021458) = 14.7 \ \text{N} \times (-0.5707226654021458) = -7.941532711021528 \ \text{N} \][/tex]

5. Calculate the total normal force:
The normal force [tex]\( n \)[/tex] is the sum of the gravitational force and the vertical component of the applied force:
[tex]\[ n = F_g + F_v \][/tex]
Substituting the values:
[tex]\[ n = 71.8092 \ \text{N} + (-7.941532711021528 \ \text{N}) = 63.867667288978474 \ \text{N} \][/tex]

Thus, the total normal force acting on the cart is:
[tex]\[ n = 63.867667288978474 \ \text{N} \][/tex]