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\begin{tabular}{|c|c|}
\hline \multicolumn{2}{|c|}{Angle Measure Conversion} \\
\hline Degrees & Gradients \\
\hline -180 & -200 \\
\hline -90 & -100 \\
\hline 0 & 0 \\
\hline 90 & 100 \\
\hline 180 & 200 \\
\hline 270 & 300 \\
\hline
\end{tabular}

Engineers measure angles in gradients, which are smaller than degrees. The table shows the conversion of some angle measures in degrees to angles in gradients. What is the slope of the line representing the conversion of degrees to gradients?

Express your answer as a decimal rounded to the nearest hundredth.
[tex]$\square$[/tex]

Sagot :

To find the slope of the line that represents the conversion of degrees to gradients, we can follow these steps:

1. Identify Two Points:
First, select two points from the given table:
- Point A: [tex]\((-180, -200)\)[/tex]
- Point B: [tex]\((-90, -100)\)[/tex]

2. Calculate the Slope:
The slope ([tex]\( m \)[/tex]) of a line passing through two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex] is given by the formula:
[tex]\[ m = \frac{y_2 - y_1}{x_2 - x_1} \][/tex]

Substituting in the coordinates of our selected points:
[tex]\[ m = \frac{-100 - (-200)}{-90 - (-180)} = \frac{-100 + 200}{-90 + 180} = \frac{100}{90} = \frac{10}{9} \approx 1.1111111111111112 \][/tex]

3. Round the Slope:
To provide the slope rounded to the nearest hundredth, we can round 1.1111111111111112.

Rounded to the nearest hundredth, we get:
[tex]\[ 1.11 \][/tex]

Therefore, the slope of the line representing the conversion of degrees to gradients is [tex]\( \boxed{1.11} \)[/tex].
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