Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To find the product of the binomials [tex]\(\left(-2d^2 + s\right)\left(5d^2 - 6s\right)\)[/tex], we can use the distributive property (also known as the FOIL method for binomials). Let’s go through the steps:
1. First terms: Multiply the first terms in each binomial: [tex]\(-2d^2 \cdot 5d^2\)[/tex].
[tex]\[ -2d^2 \cdot 5d^2 = -10d^4 \][/tex]
2. Outer terms: Multiply the outer terms in each binomial: [tex]\(-2d^2 \cdot -6s\)[/tex].
[tex]\[ -2d^2 \cdot -6s = 12d^2s \][/tex]
3. Inner terms: Multiply the inner terms in each binomial: [tex]\(s \cdot 5d^2\)[/tex].
[tex]\[ s \cdot 5d^2 = 5d^2s \][/tex]
4. Last terms: Multiply the last terms in each binomial: [tex]\(s \cdot -6s\)[/tex].
[tex]\[ s \cdot -6s = -6s^2 \][/tex]
Now, add all these products together:
[tex]\[ -10d^4 + 12d^2s + 5d^2s - 6s^2 \][/tex]
Combine the like terms ([tex]\(12d^2s\)[/tex] and [tex]\(5d^2s\)[/tex]):
[tex]\[ -10d^4 + (12d^2s + 5d^2s) - 6s^2 \][/tex]
[tex]\[ -10d^4 + 17d^2s - 6s^2 \][/tex]
So, the product of [tex]\(\left(-2d^2 + s\right) \left(5d^2 - 6s\right)\)[/tex] is:
[tex]\[ \boxed{-10d^4 + 17d^2s - 6s^2} \][/tex]
Therefore, the correct answer is:
[tex]\[ -10 d^4 + 17 d^2 s - 6 s^2 \][/tex]
1. First terms: Multiply the first terms in each binomial: [tex]\(-2d^2 \cdot 5d^2\)[/tex].
[tex]\[ -2d^2 \cdot 5d^2 = -10d^4 \][/tex]
2. Outer terms: Multiply the outer terms in each binomial: [tex]\(-2d^2 \cdot -6s\)[/tex].
[tex]\[ -2d^2 \cdot -6s = 12d^2s \][/tex]
3. Inner terms: Multiply the inner terms in each binomial: [tex]\(s \cdot 5d^2\)[/tex].
[tex]\[ s \cdot 5d^2 = 5d^2s \][/tex]
4. Last terms: Multiply the last terms in each binomial: [tex]\(s \cdot -6s\)[/tex].
[tex]\[ s \cdot -6s = -6s^2 \][/tex]
Now, add all these products together:
[tex]\[ -10d^4 + 12d^2s + 5d^2s - 6s^2 \][/tex]
Combine the like terms ([tex]\(12d^2s\)[/tex] and [tex]\(5d^2s\)[/tex]):
[tex]\[ -10d^4 + (12d^2s + 5d^2s) - 6s^2 \][/tex]
[tex]\[ -10d^4 + 17d^2s - 6s^2 \][/tex]
So, the product of [tex]\(\left(-2d^2 + s\right) \left(5d^2 - 6s\right)\)[/tex] is:
[tex]\[ \boxed{-10d^4 + 17d^2s - 6s^2} \][/tex]
Therefore, the correct answer is:
[tex]\[ -10 d^4 + 17 d^2 s - 6 s^2 \][/tex]
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.