Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Certainly! Let's go through the detailed steps of solving the given division of a polynomial by a linear expression.
We are given the expression [tex]\((-3x^4 + 7x^2 + 1) \div (x - 1)\)[/tex].
Step 1: Write down the polynomial and the divisor.
- Polynomial: [tex]\(-3x^4 + 7x^2 + 1\)[/tex]
- Divisor: [tex]\(x - 1\)[/tex]
Step 2: Set up the long division for polynomials.
Firstly, we arrange both the polynomial and the divisor in the standard form (descending powers of [tex]\(x\)[/tex]):
[tex]\[ \frac{-3x^4 + 0x^3 + 7x^2 + 0x + 1}{x - 1} \][/tex]
Step 3: Divide the first term of the numerator by the first term of the divisor to get the first term of the quotient.
[tex]\[ \frac{-3x^4}{x} = -3x^3 \][/tex]
Step 4: Multiply the divisor by this term and subtract from the polynomial.
[tex]\[ (-3x^3)(x - 1) = -3x^4 + 3x^3 \][/tex]
[tex]\[ \left(-3x^4 + 0x^3 + 7x^2 + 0x + 1\right) - \left(-3x^4 + 3x^3\right) = 0x^4 - 3x^3 + 7x^2 + 0x + 1 \][/tex]
Step 5: Repeat the process with the new polynomial.
Now we proceed with the polynomial [tex]\(-3x^3 + 7x^2 + 0x + 1\)[/tex].
[tex]\[ \frac{-3x^3}{x} = -3x^2 \][/tex]
[tex]\[ (-3x^2)(x - 1) = -3x^3 + 3x^2 \][/tex]
[tex]\[ \left(-3x^3 + 7x^2 + 0x + 1\right) - \left(-3x^3 + 3x^2\right) = 0x^3 + 4x^2 + 0x + 1 \][/tex]
Step 6: Continue the process with the remaining polynomial.
Next, we use the polynomial [tex]\(4x^2 + 0x + 1\)[/tex].
[tex]\[ \frac{4x^2}{x} = 4x \][/tex]
[tex]\[ (4x)(x - 1) = 4x^2 - 4x \][/tex]
[tex]\[ \left(4x^2 + 0x + 1\right) - \left(4x^2 - 4x\right) = 4x + 1 \][/tex]
Step 7: One last step with the remaining polynomial.
Finally, we consider the polynomial [tex]\(4x + 1\)[/tex].
[tex]\[ \frac{4x}{x} = 4 \][/tex]
[tex]\[ (4)(x - 1) = 4x - 4 \][/tex]
[tex]\[ \left(4x + 1\right) - \left(4x - 4\right) = 5 \][/tex]
Step 8: No further division is possible because the remainder degree [tex]\(5\)[/tex] is less than the divisor's degree [tex]\(1\)[/tex].
Therefore, the division of [tex]\((-3x^4 + 7x^2 + 1)\)[/tex] by [tex]\((x - 1)\)[/tex] yields a polynomial plus a remainder. However, considering the simplified form where no further reduction is made, the expression remains as:
[tex]\[ \boxed{\frac{-3x^4 + 7x^2 + 1}{x - 1}} \][/tex]
We are given the expression [tex]\((-3x^4 + 7x^2 + 1) \div (x - 1)\)[/tex].
Step 1: Write down the polynomial and the divisor.
- Polynomial: [tex]\(-3x^4 + 7x^2 + 1\)[/tex]
- Divisor: [tex]\(x - 1\)[/tex]
Step 2: Set up the long division for polynomials.
Firstly, we arrange both the polynomial and the divisor in the standard form (descending powers of [tex]\(x\)[/tex]):
[tex]\[ \frac{-3x^4 + 0x^3 + 7x^2 + 0x + 1}{x - 1} \][/tex]
Step 3: Divide the first term of the numerator by the first term of the divisor to get the first term of the quotient.
[tex]\[ \frac{-3x^4}{x} = -3x^3 \][/tex]
Step 4: Multiply the divisor by this term and subtract from the polynomial.
[tex]\[ (-3x^3)(x - 1) = -3x^4 + 3x^3 \][/tex]
[tex]\[ \left(-3x^4 + 0x^3 + 7x^2 + 0x + 1\right) - \left(-3x^4 + 3x^3\right) = 0x^4 - 3x^3 + 7x^2 + 0x + 1 \][/tex]
Step 5: Repeat the process with the new polynomial.
Now we proceed with the polynomial [tex]\(-3x^3 + 7x^2 + 0x + 1\)[/tex].
[tex]\[ \frac{-3x^3}{x} = -3x^2 \][/tex]
[tex]\[ (-3x^2)(x - 1) = -3x^3 + 3x^2 \][/tex]
[tex]\[ \left(-3x^3 + 7x^2 + 0x + 1\right) - \left(-3x^3 + 3x^2\right) = 0x^3 + 4x^2 + 0x + 1 \][/tex]
Step 6: Continue the process with the remaining polynomial.
Next, we use the polynomial [tex]\(4x^2 + 0x + 1\)[/tex].
[tex]\[ \frac{4x^2}{x} = 4x \][/tex]
[tex]\[ (4x)(x - 1) = 4x^2 - 4x \][/tex]
[tex]\[ \left(4x^2 + 0x + 1\right) - \left(4x^2 - 4x\right) = 4x + 1 \][/tex]
Step 7: One last step with the remaining polynomial.
Finally, we consider the polynomial [tex]\(4x + 1\)[/tex].
[tex]\[ \frac{4x}{x} = 4 \][/tex]
[tex]\[ (4)(x - 1) = 4x - 4 \][/tex]
[tex]\[ \left(4x + 1\right) - \left(4x - 4\right) = 5 \][/tex]
Step 8: No further division is possible because the remainder degree [tex]\(5\)[/tex] is less than the divisor's degree [tex]\(1\)[/tex].
Therefore, the division of [tex]\((-3x^4 + 7x^2 + 1)\)[/tex] by [tex]\((x - 1)\)[/tex] yields a polynomial plus a remainder. However, considering the simplified form where no further reduction is made, the expression remains as:
[tex]\[ \boxed{\frac{-3x^4 + 7x^2 + 1}{x - 1}} \][/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.