The path of a pumpkin launched from a compressed air cannon is modeled by f(x) = -3/10,000x²+3/2x+28, where f(x) is the height (in feet) and x is the horizontal distance in feet) from where the pumpkin was launched.
How high (in ft) is the pumpkin when it is launched?

Question

26-06-2024
Mathematics

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The path of a pumpkin launched from a compressed air cannon is modeled by f(x) = -3/10,000x²+3/2x+28, where f(x) is the height (in feet) and x is the horizontal distance in feet) from where the pumpkin was launched.
How high (in ft) is the pumpkin when it is launched?

Sagot :

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The path of a pumpkin launched from a compressed air cannon is modeled by f(x) = -3/10,000x²+3/2x+28, where f(x) is the height (in feet) and x is the horizontal distance in feet) from where the pumpkin was launched. How high (in ft) is the pumpkin when it is launched?

Sagot :

Other Questions

The path of a pumpkin launched from a compressed air cannon is modeled by f(x) = -3/10,000x²+3/2x+28, where f(x) is the height (in feet) and x is the horizontal distance in feet) from where the pumpkin was launched.
How high (in ft) is the pumpkin when it is launched?