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Find the perimeter of a triangle with the following side lengths:

[tex]-8a, (a + 4), (12a + 10)[/tex]

Sagot :

To find the perimeter of a triangle, you need to sum the lengths of all its sides.

The given side lengths of the triangle are:
- [tex]\( -8a \)[/tex]
- [tex]\( a + 4 \)[/tex]
- [tex]\( 12a + 10 \)[/tex]

Step-by-Step Solution:

1. Identify the side lengths:
- First side length: [tex]\( -8a \)[/tex]
- Second side length: [tex]\( a + 4 \)[/tex]
- Third side length: [tex]\( 12a + 10 \)[/tex]

2. Sum up all the side lengths:
[tex]\[ \text{Perimeter} = (-8a) + (a + 4) + (12a + 10) \][/tex]

3. Combine like terms:
- Combine the [tex]\(a\)[/tex] terms: [tex]\( -8a + a + 12a = (-8 + 1 + 12)a = 5a \)[/tex]
- Combine the constants: [tex]\(4 + 10 = 14\)[/tex]

4. Simplify the expression:
[tex]\[ \text{Perimeter} = 5a + 14 \][/tex]

Thus, the perimeter of the triangle is given by the expression [tex]\( 5a + 14 \)[/tex].

Given that the numerical result provided is:
[tex]\[ 18 \][/tex]

This implies that if we substitute the correct value of [tex]\( a \)[/tex], the expression [tex]\(5a + 14\)[/tex] yields [tex]\(18\)[/tex].
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