Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
To determine the probability of picking a green disk, we start by analyzing the information given in the question. The table provides the probabilities for picking disks of three specific colors: Red, Blue, and Brown. The probabilities are as follows:
- Probability of picking a red disk (P(Red)) = 0.1
- Probability of picking a blue disk (P(Blue)) = 0.25
- Probability of picking a brown disk (P(Brown)) = 0.3
We know that the total probability for picking any disk from the bag must be equal to 1, because probability is a measure of certainty for all possible outcomes, and we are certain that a disk selected will have one of the given colors.
The total probability (P(Total)) is given by the sum of the probabilities of all the colors:
[tex]\[ P(Total) = 1.0 \][/tex]
Given that there are no other colors besides Red, Blue, Green, and Brown, we can write:
[tex]\[ P(Total) = P(Red) + P(Blue) + P(Green) + P(Brown) \][/tex]
To find the probability of picking a green disk (P(Green)), we rearrange the equation to solve for [tex]\( P(Green) \)[/tex]:
[tex]\[ P(Green) = P(Total) - (P(Red) + P(Blue) + P(Brown)) \][/tex]
Now, we substitute the values we have for the given probabilities:
[tex]\[ P(Green) = 1.0 - (0.1 + 0.25 + 0.3) \][/tex]
Next, we perform the addition inside the parentheses:
[tex]\[ 0.1 + 0.25 + 0.3 = 0.65 \][/tex]
Therefore, we have:
[tex]\[ P(Green) = 1.0 - 0.65 \][/tex]
Finally, we subtract to find the probability of picking a green disk:
[tex]\[ P(Green) = 0.35 \][/tex]
So, the probability of picking a green disk is:
[tex]\[ P(Green) = 0.3500000000000001 \][/tex]
This small discrepancy beyond [tex]\(0.35\)[/tex] occurs due to floating-point precision in calculations, but for practical purposes, we usually refer to it as approximately [tex]\(0.35\)[/tex].
Thus, the probability of picking a green disk is [tex]\(0.35\)[/tex].
- Probability of picking a red disk (P(Red)) = 0.1
- Probability of picking a blue disk (P(Blue)) = 0.25
- Probability of picking a brown disk (P(Brown)) = 0.3
We know that the total probability for picking any disk from the bag must be equal to 1, because probability is a measure of certainty for all possible outcomes, and we are certain that a disk selected will have one of the given colors.
The total probability (P(Total)) is given by the sum of the probabilities of all the colors:
[tex]\[ P(Total) = 1.0 \][/tex]
Given that there are no other colors besides Red, Blue, Green, and Brown, we can write:
[tex]\[ P(Total) = P(Red) + P(Blue) + P(Green) + P(Brown) \][/tex]
To find the probability of picking a green disk (P(Green)), we rearrange the equation to solve for [tex]\( P(Green) \)[/tex]:
[tex]\[ P(Green) = P(Total) - (P(Red) + P(Blue) + P(Brown)) \][/tex]
Now, we substitute the values we have for the given probabilities:
[tex]\[ P(Green) = 1.0 - (0.1 + 0.25 + 0.3) \][/tex]
Next, we perform the addition inside the parentheses:
[tex]\[ 0.1 + 0.25 + 0.3 = 0.65 \][/tex]
Therefore, we have:
[tex]\[ P(Green) = 1.0 - 0.65 \][/tex]
Finally, we subtract to find the probability of picking a green disk:
[tex]\[ P(Green) = 0.35 \][/tex]
So, the probability of picking a green disk is:
[tex]\[ P(Green) = 0.3500000000000001 \][/tex]
This small discrepancy beyond [tex]\(0.35\)[/tex] occurs due to floating-point precision in calculations, but for practical purposes, we usually refer to it as approximately [tex]\(0.35\)[/tex].
Thus, the probability of picking a green disk is [tex]\(0.35\)[/tex].
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.