Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To determine the probability of picking a green disk, we start by analyzing the information given in the question. The table provides the probabilities for picking disks of three specific colors: Red, Blue, and Brown. The probabilities are as follows:
- Probability of picking a red disk (P(Red)) = 0.1
- Probability of picking a blue disk (P(Blue)) = 0.25
- Probability of picking a brown disk (P(Brown)) = 0.3
We know that the total probability for picking any disk from the bag must be equal to 1, because probability is a measure of certainty for all possible outcomes, and we are certain that a disk selected will have one of the given colors.
The total probability (P(Total)) is given by the sum of the probabilities of all the colors:
[tex]\[ P(Total) = 1.0 \][/tex]
Given that there are no other colors besides Red, Blue, Green, and Brown, we can write:
[tex]\[ P(Total) = P(Red) + P(Blue) + P(Green) + P(Brown) \][/tex]
To find the probability of picking a green disk (P(Green)), we rearrange the equation to solve for [tex]\( P(Green) \)[/tex]:
[tex]\[ P(Green) = P(Total) - (P(Red) + P(Blue) + P(Brown)) \][/tex]
Now, we substitute the values we have for the given probabilities:
[tex]\[ P(Green) = 1.0 - (0.1 + 0.25 + 0.3) \][/tex]
Next, we perform the addition inside the parentheses:
[tex]\[ 0.1 + 0.25 + 0.3 = 0.65 \][/tex]
Therefore, we have:
[tex]\[ P(Green) = 1.0 - 0.65 \][/tex]
Finally, we subtract to find the probability of picking a green disk:
[tex]\[ P(Green) = 0.35 \][/tex]
So, the probability of picking a green disk is:
[tex]\[ P(Green) = 0.3500000000000001 \][/tex]
This small discrepancy beyond [tex]\(0.35\)[/tex] occurs due to floating-point precision in calculations, but for practical purposes, we usually refer to it as approximately [tex]\(0.35\)[/tex].
Thus, the probability of picking a green disk is [tex]\(0.35\)[/tex].
- Probability of picking a red disk (P(Red)) = 0.1
- Probability of picking a blue disk (P(Blue)) = 0.25
- Probability of picking a brown disk (P(Brown)) = 0.3
We know that the total probability for picking any disk from the bag must be equal to 1, because probability is a measure of certainty for all possible outcomes, and we are certain that a disk selected will have one of the given colors.
The total probability (P(Total)) is given by the sum of the probabilities of all the colors:
[tex]\[ P(Total) = 1.0 \][/tex]
Given that there are no other colors besides Red, Blue, Green, and Brown, we can write:
[tex]\[ P(Total) = P(Red) + P(Blue) + P(Green) + P(Brown) \][/tex]
To find the probability of picking a green disk (P(Green)), we rearrange the equation to solve for [tex]\( P(Green) \)[/tex]:
[tex]\[ P(Green) = P(Total) - (P(Red) + P(Blue) + P(Brown)) \][/tex]
Now, we substitute the values we have for the given probabilities:
[tex]\[ P(Green) = 1.0 - (0.1 + 0.25 + 0.3) \][/tex]
Next, we perform the addition inside the parentheses:
[tex]\[ 0.1 + 0.25 + 0.3 = 0.65 \][/tex]
Therefore, we have:
[tex]\[ P(Green) = 1.0 - 0.65 \][/tex]
Finally, we subtract to find the probability of picking a green disk:
[tex]\[ P(Green) = 0.35 \][/tex]
So, the probability of picking a green disk is:
[tex]\[ P(Green) = 0.3500000000000001 \][/tex]
This small discrepancy beyond [tex]\(0.35\)[/tex] occurs due to floating-point precision in calculations, but for practical purposes, we usually refer to it as approximately [tex]\(0.35\)[/tex].
Thus, the probability of picking a green disk is [tex]\(0.35\)[/tex].
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.