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What is the [tex]$pH[tex]$[/tex] of a solution with a [tex]$[/tex]3.2 \times 10^{-5} M$[/tex] hydronium ion concentration?

A. 4.3
B. 4.5
C. 11
D. 12

Sagot :

To determine the \( pH \) of a solution with a hydronium ion concentration \([H_3O^+]\) of \( 3.2 \times 10^{-5} \) M, you need to use the formula for pH, which is:

[tex]\[ pH = -\log_{10}([H_3O^+]) \][/tex]

Here are the steps to solve the problem:

1. Identify the hydronium ion concentration:
[tex]\[ [H_3O^+] = 3.2 \times 10^{-5} \][/tex]

2. Apply the pH formula:
[tex]\[ pH = -\log_{10}(3.2 \times 10^{-5}) \][/tex]

3. Calculate the logarithm:
Use a calculator to find the base 10 logarithm of \( 3.2 \times 10^{-5} \).

[tex]\[ \log_{10}(3.2 \times 10^{-5}) \approx -4.49485 \][/tex]

4. Convert to positive pH value:
[tex]\[ pH = -(-4.49485) = 4.49485 \][/tex]

Now, round the result to one decimal place to match the options provided.

[tex]\[ pH \approx 4.5 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{4.5} \][/tex]