Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Our Q&A platform offers a seamless experience for finding reliable answers from experts in various disciplines. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

What is the [tex]$pH[tex]$[/tex] of a solution with a [tex]$[/tex]3.2 \times 10^{-5} M$[/tex] hydronium ion concentration?

A. 4.3
B. 4.5
C. 11
D. 12


Sagot :

To determine the \( pH \) of a solution with a hydronium ion concentration \([H_3O^+]\) of \( 3.2 \times 10^{-5} \) M, you need to use the formula for pH, which is:

[tex]\[ pH = -\log_{10}([H_3O^+]) \][/tex]

Here are the steps to solve the problem:

1. Identify the hydronium ion concentration:
[tex]\[ [H_3O^+] = 3.2 \times 10^{-5} \][/tex]

2. Apply the pH formula:
[tex]\[ pH = -\log_{10}(3.2 \times 10^{-5}) \][/tex]

3. Calculate the logarithm:
Use a calculator to find the base 10 logarithm of \( 3.2 \times 10^{-5} \).

[tex]\[ \log_{10}(3.2 \times 10^{-5}) \approx -4.49485 \][/tex]

4. Convert to positive pH value:
[tex]\[ pH = -(-4.49485) = 4.49485 \][/tex]

Now, round the result to one decimal place to match the options provided.

[tex]\[ pH \approx 4.5 \][/tex]

Thus, the correct answer is:
[tex]\[ \boxed{4.5} \][/tex]