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In a class of 60 students, 70% failed in English, 60% failed in Nepali and 50% failed in both subjects. Find how many students pass in both subject?​

Sagot :

Answer:Let's define the following:

- \( E \) = number of students who failed in English.

- \( N \) = number of students who failed in Nepali.

- \( EN \) = number of students who failed in both English and Nepali.

- \( P \) = number of students who passed in both subjects.

From the problem, we have:

- Total number of students = 60

- 70% failed in English, so \( E = 0.7 \times 60 = 42 \)

- 60% failed in Nepali, so \( N = 0.6 \times 60 = 36 \)

- 50% failed in both subjects, so \( EN = 0.5 \times 60 = 30 \)

We can use the principle of inclusion and exclusion to find the number of students who failed in at least one subject:

\[

E + N - EN = 42 + 36 - 30 = 48

\]

So, the number of students who failed in at least one subject is 48.

Therefore, the number of students who passed in both subjects is:

\[

P = 60 - 48 = 12

\]

So, 12 students passed in both subjects.

Step-by-step explanation: