Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get the answers you need quickly and accurately from a dedicated community of experts on our Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
To find the midpoint of the line segment \(\overline{GH}\), we use the midpoint formula. The formula for the midpoint, \(M\), between two points \(G(x_1, y_1)\) and \(H(x_2, y_2)\) in a coordinate plane is given by:
[tex]\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]
Given the endpoints \(G(14, 3)\) and \(H(10, -6)\), let's identify the coordinates clearly:
- \(G\) has coordinates \((x_1, y_1) = (14, 3)\)
- \(H\) has coordinates \((x_2, y_2) = (10, -6)\)
We substitute these coordinates into the midpoint formula:
1. Calculate the x-coordinate of the midpoint:
[tex]\[ \frac{x_1 + x_2}{2} = \frac{14 + 10}{2} = \frac{24}{2} = 12 \][/tex]
2. Calculate the y-coordinate of the midpoint:
[tex]\[ \frac{y_1 + y_2}{2} = \frac{3 + (-6)}{2} = \frac{3 - 6}{2} = \frac{-3}{2} = -1.5 \][/tex]
Therefore, the coordinates of the midpoint \(M\) are:
[tex]\[ M = \left(12, -1.5\right) \][/tex]
The correct answer is:
C. [tex]\(\left(12, -\frac{3}{2}\right)\)[/tex]
[tex]\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \][/tex]
Given the endpoints \(G(14, 3)\) and \(H(10, -6)\), let's identify the coordinates clearly:
- \(G\) has coordinates \((x_1, y_1) = (14, 3)\)
- \(H\) has coordinates \((x_2, y_2) = (10, -6)\)
We substitute these coordinates into the midpoint formula:
1. Calculate the x-coordinate of the midpoint:
[tex]\[ \frac{x_1 + x_2}{2} = \frac{14 + 10}{2} = \frac{24}{2} = 12 \][/tex]
2. Calculate the y-coordinate of the midpoint:
[tex]\[ \frac{y_1 + y_2}{2} = \frac{3 + (-6)}{2} = \frac{3 - 6}{2} = \frac{-3}{2} = -1.5 \][/tex]
Therefore, the coordinates of the midpoint \(M\) are:
[tex]\[ M = \left(12, -1.5\right) \][/tex]
The correct answer is:
C. [tex]\(\left(12, -\frac{3}{2}\right)\)[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.