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Consider the reaction below.

[tex]\[ 2 C_6H_{14} + 19 O_2 \rightarrow 12 CO_2 + 14 H_2O \][/tex]

How many moles of hexane \(\left( C_6H_{14} \right)\) must burn to form 18.4 mol of carbon dioxide?

A. 1.53 mol
B. 3.07 mol
C. 110. mol
D. 175. mol

Sagot :

Sure, let's go through the problem step-by-step to find out how many moles of hexane (C₆H₁₄) are required to form 18.4 moles of carbon dioxide (CO₂) based on the given chemical reaction:

[tex]\[ 2 \text{ C}_6\text{H}_{14} + 19 \text{ O}_2 \rightarrow 12 \text{ CO}_2 + 14 \text{ H}_2\text{O} \][/tex]

1. Identify the stoichiometric ratio:
The balanced chemical equation tells us that 2 moles of C₆H₁₄ produce 12 moles of CO₂.

2. Form the proportion:
We need to form a proportion to find the moles of C₆H₁₄ required to produce a given amount of CO₂. According to the equation:
[tex]\[ \frac{2 \text{ moles of C}_6\text{H}_{14}}{12 \text{ moles of CO}_2} = \frac{x \text{ moles of C}_6\text{H}_{14}}{18.4 \text{ moles of CO}_2} \][/tex]
Here, \( x \) represents the moles of C₆H₁₄ we need to find.

3. Solve the proportion:
We can solve for \( x \) by cross-multiplying and then isolating \( x \):
[tex]\[ x = \frac{2 \text{ moles of C}_6\text{H}_{14} \times 18.4 \text{ moles of CO}_2}{12 \text{ moles of CO}_2} \][/tex]
[tex]\[ x = \frac{36.8}{12} \][/tex]

4. Calculate the result:
Divide 36.8 by 12:
[tex]\[ x \approx 3.07 \text{ moles of C}_6\text{H}_{14} \][/tex]

Therefore, the number of moles of hexane (C₆H₁₄) required to form 18.4 moles of carbon dioxide (CO₂) is approximately [tex]\( \boxed{3.07} \text{ moles} \)[/tex].