At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Ask your questions and receive precise answers from experienced professionals across different disciplines. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

The provided text appears to be garbled and lacks context. Here's a possible reconstruction that makes sense based on the information given:

---

Jesse's score: [tex]-7[/tex]

Tyree's score: [tex]3x^2 + 15[/tex]

---

Without additional context or specific instructions, it's challenging to determine the exact intent of the question, but this format follows the given structure and ensures clarity.


Sagot :

Of course! Let's break down the details step-by-step to solve this problem. It seems there are a few typos, so let's correct and clarify the question first:

Let's assume the problem involves Olivia with the following details:

- Olivia initially has $23.
- She buys 5 bagels.
- Each bagel costs $3.

Now, let's solve it step-by-step.

1. Initial amount of money Olivia has:
Olivia starts with $23.

2. Number of bagels purchased:
Olivia buys 5 bagels.

3. Cost of each bagel:
Each bagel costs $3.

4. Calculate the total amount of money spent on bagels:
We need to find out how much Olivia spends on all the bagels. Since each bagel costs $3 and she buys 5 bagels, the total cost is calculated as:
[tex]\[ \text{Total Cost} = \text{Number of Bagels} \times \text{Cost per Bagel} = 5 \times 3 = 15 \][/tex]

5. Calculate how much money Olivia has left:
We subtract the amount of money spent on the bagels from Olivia's initial amount of money:
[tex]\[ \text{Money Left} = \text{Initial Amount} - \text{Total Cost} = 23 - 15 = 8 \][/tex]

So, after buying 5 bagels, Olivia spends [tex]$15 and has $[/tex]8 left.

Thus, Olivia spends [tex]$15 on bagels and has $[/tex]8 left.

Remember, it's important to carefully follow the steps and ensure clarity of the calculations at each stage to ensure accuracy.