Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Let's solve the equation \(\frac{\cos A - \sin A}{\cos A + \sin A} = \sec(2A) - \tan(2A)\) step by step.
First, consider the left-hand side of the equation:
[tex]\[ \text{Left-hand side: } \frac{\cos A - \sin A}{\cos A + \sin A} \][/tex]
Next, let's consider the right-hand side of the equation:
[tex]\[ \text{Right-hand side: } \sec(2A) - \tan(2A) \][/tex]
Now let's break it down.
### Simplifying the Left-Hand Side
The left-hand side is already in a simplified form involving trigonometric functions:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} \][/tex]
### Simplifying the Right-Hand Side
Evaluate the right-hand side using known trigonometric identities:
[tex]\[ \sec(2A) = \frac{1}{\cos(2A)}, \quad \tan(2A) = \frac{\sin(2A)}{\cos(2A)} \][/tex]
Thus, the right-hand side can be written as:
[tex]\[ \sec(2A) - \tan(2A) = \frac{1}{\cos(2A)} - \frac{\sin(2A)}{\cos(2A)} = \frac{1 - \sin(2A)}{\cos(2A)} \][/tex]
### Comparing Both Sides
To check the equality, let's compare:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} \quad \text{and} \quad \frac{1 - \sin(2A)}{\cos(2A)} \][/tex]
Upon simplifying expressions and calculations, we find that:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} = \frac{1}{\tan(A + \frac{\pi}{4})} \][/tex]
Whereas:
[tex]\[ \sec(2A) - \tan(2A) = -\tan(2A) + \sec(2A) \][/tex]
### Conclusion
Upon simplification, it is evident that the two expressions:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} \quad \text{and} \quad \sec(2A) - \tan(2A) \][/tex]
do not simplify to the same value. Hence, the given equation:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} = \sec(2A) - \tan(2A) \][/tex]
is not true.
First, consider the left-hand side of the equation:
[tex]\[ \text{Left-hand side: } \frac{\cos A - \sin A}{\cos A + \sin A} \][/tex]
Next, let's consider the right-hand side of the equation:
[tex]\[ \text{Right-hand side: } \sec(2A) - \tan(2A) \][/tex]
Now let's break it down.
### Simplifying the Left-Hand Side
The left-hand side is already in a simplified form involving trigonometric functions:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} \][/tex]
### Simplifying the Right-Hand Side
Evaluate the right-hand side using known trigonometric identities:
[tex]\[ \sec(2A) = \frac{1}{\cos(2A)}, \quad \tan(2A) = \frac{\sin(2A)}{\cos(2A)} \][/tex]
Thus, the right-hand side can be written as:
[tex]\[ \sec(2A) - \tan(2A) = \frac{1}{\cos(2A)} - \frac{\sin(2A)}{\cos(2A)} = \frac{1 - \sin(2A)}{\cos(2A)} \][/tex]
### Comparing Both Sides
To check the equality, let's compare:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} \quad \text{and} \quad \frac{1 - \sin(2A)}{\cos(2A)} \][/tex]
Upon simplifying expressions and calculations, we find that:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} = \frac{1}{\tan(A + \frac{\pi}{4})} \][/tex]
Whereas:
[tex]\[ \sec(2A) - \tan(2A) = -\tan(2A) + \sec(2A) \][/tex]
### Conclusion
Upon simplification, it is evident that the two expressions:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} \quad \text{and} \quad \sec(2A) - \tan(2A) \][/tex]
do not simplify to the same value. Hence, the given equation:
[tex]\[ \frac{\cos A - \sin A}{\cos A + \sin A} = \sec(2A) - \tan(2A) \][/tex]
is not true.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.