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Sagot :
Sure! Let's set up the subtraction of the two polynomials in a vertical format and work through it step-by-step.
We need to subtract \( -4 + 3a^2 \) from \( 7a - a^2 \).
First, let's write the polynomials in a standard form and stack them vertically:
[tex]\[ \begin{array}{r} 7a - a^2 \\ -( - 4 + 3a^2) \\ \end{array} \][/tex]
When we subtract polynomials, we change the sign of all the terms in the polynomial being subtracted and then combine like terms. Therefore:
Original:
[tex]\[ 7a - a^2 \][/tex]
Subtracting \(-4 + 3a^2\):
[tex]\[ -( - 4 + 3a^2 ) = 4 - 3a^2 \][/tex]
Now, line up and change the signs:
[tex]\[ \begin{array}{r} 7a - a^2 \\ 4 - 3a^2 \\ \end{array} \][/tex]
Combine like terms:
[tex]\[ \begin{array}{r} - a^2 - 3a^2 + 7a + 4 \\ = -4a^2 + 7a + 4 \end{array} \][/tex]
So, the result of subtracting \(-4 + 3a^2\) from \(7a - a^2\) is:
[tex]\[ -4a^2 + 7a + 4 \][/tex]
Thus, the correct answer is:
[tex]\[ \boxed{-4a^2 + 7a + 4} \][/tex]
We need to subtract \( -4 + 3a^2 \) from \( 7a - a^2 \).
First, let's write the polynomials in a standard form and stack them vertically:
[tex]\[ \begin{array}{r} 7a - a^2 \\ -( - 4 + 3a^2) \\ \end{array} \][/tex]
When we subtract polynomials, we change the sign of all the terms in the polynomial being subtracted and then combine like terms. Therefore:
Original:
[tex]\[ 7a - a^2 \][/tex]
Subtracting \(-4 + 3a^2\):
[tex]\[ -( - 4 + 3a^2 ) = 4 - 3a^2 \][/tex]
Now, line up and change the signs:
[tex]\[ \begin{array}{r} 7a - a^2 \\ 4 - 3a^2 \\ \end{array} \][/tex]
Combine like terms:
[tex]\[ \begin{array}{r} - a^2 - 3a^2 + 7a + 4 \\ = -4a^2 + 7a + 4 \end{array} \][/tex]
So, the result of subtracting \(-4 + 3a^2\) from \(7a - a^2\) is:
[tex]\[ -4a^2 + 7a + 4 \][/tex]
Thus, the correct answer is:
[tex]\[ \boxed{-4a^2 + 7a + 4} \][/tex]
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