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Sagot :
Let's complete the table based on the given domain \(\{-12, -6, 3, 15\}\) for the function \(y = -\frac{2}{3}x + 7\).
1. For \(x = -12\):
[tex]\[ y = -\frac{2}{3}(-12) + 7 = 8 + 7 = 15 \][/tex]
2. For \(x = -6\):
[tex]\[ y = -\frac{2}{3}(-6) + 7 = 4 + 7 = 11 \][/tex]
3. For \(x = 3\):
[tex]\[ y = -\frac{2}{3}(3) + 7 = -2 + 7 = 5 \][/tex]
4. For \(x = 15\):
[tex]\[ y = -\frac{2}{3}(15) + 7 = -10 + 7 = -3 \][/tex]
Let’s fill in the table with these calculations:
[tex]\[ \begin{tabular}{|c|c|} \hline [tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline
-12 & 15 \\
\hline
-6 & 11 \\
\hline
3 & 5 \\
\hline
15 & -3 \\
\hline
\end{tabular}
\][/tex]
1. For \(x = -12\):
[tex]\[ y = -\frac{2}{3}(-12) + 7 = 8 + 7 = 15 \][/tex]
2. For \(x = -6\):
[tex]\[ y = -\frac{2}{3}(-6) + 7 = 4 + 7 = 11 \][/tex]
3. For \(x = 3\):
[tex]\[ y = -\frac{2}{3}(3) + 7 = -2 + 7 = 5 \][/tex]
4. For \(x = 15\):
[tex]\[ y = -\frac{2}{3}(15) + 7 = -10 + 7 = -3 \][/tex]
Let’s fill in the table with these calculations:
[tex]\[ \begin{tabular}{|c|c|} \hline [tex]$x$[/tex] & [tex]$y$[/tex] \\
\hline
-12 & 15 \\
\hline
-6 & 11 \\
\hline
3 & 5 \\
\hline
15 & -3 \\
\hline
\end{tabular}
\][/tex]
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