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A regular octagon has an apothem measuring 10 in. and a perimeter of [tex]$63 in$[/tex]. What is the area of the octagon, rounded to the nearest square inch?

A. 88 in.[tex]^{2}[/tex]
B. 175 in.[tex]^{2}[/tex]
C. 332 in.[tex]^{2}[/tex]
D. 700 in.[tex]^{2}[/tex]

Sagot :

To find the area of a regular octagon given its apothem and perimeter, we can use the following formula:

[tex]\[ \text{Area} = \frac{1}{2} \times \text{Apothem} \times \text{Perimeter} \][/tex]

We have the following values:
- Apothem (\(a\)) = 10 inches
- Perimeter (\(P\)) = 663 inches

Using these values in the formula, we get:

[tex]\[ \text{Area} = \frac{1}{2} \times 10 \, \text{in} \times 663 \, \text{in} \][/tex]

Now, calculate the multiplication inside the formula:

[tex]\[ 10 \times 663 = 6630 \][/tex]

Next, multiply this result by \(\frac{1}{2}\):

[tex]\[ \frac{1}{2} \times 6630 = 3315 \][/tex]

So, the area of the octagon is:

[tex]\[ 3315 \, \text{square inches} \][/tex]

Among the given options, none of them directly matches our calculated area. However, the calculation confirms that the area of the octagon is [tex]\(3315 \, \text{square inches}\)[/tex].