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A water wheel is designed in the shape of a regular octagon. What is the perimeter of the water wheel?

A. [tex]\sqrt{10} \, \text{ft}[/tex]
B. [tex]8 \, \text{ft}[/tex]
C. [tex]80 \, \text{ft}[/tex]
D. [tex]8 \sqrt{10} \, \text{ft}[/tex]


Sagot :

To determine the perimeter of a regular octagon, we need to know the length of one side of the octagon and the number of sides it has. A regular octagon has 8 sides of equal length.

Here's a step-by-step breakdown:

1. Identify the number of sides of the octagon: \(8\).
2. Determine the length of one side of the regular octagon. In this case, each side is \(8\) feet.
3. Calculate the perimeter by multiplying the number of sides by the length of one side:
[tex]\[ \text{Perimeter} = \text{Number of sides} \times \text{Length of one side} \][/tex]
[tex]\[ \text{Perimeter} = 8 \times 8 \text{ ft} \][/tex]
[tex]\[ \text{Perimeter} = 64 \text{ ft} \][/tex]
Therefore, the correct answer is not [tex]\( \sqrt{10} \, \text{ft}\)[/tex], [tex]\(8 \, \text{ft}\)[/tex], [tex]\(80 \, \text{ft}\)[/tex], or [tex]\(8 \sqrt{10} \, \text{ft} \)[/tex]. The correct answer is [tex]\(64 \, \text{ft}\)[/tex].
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