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Sagot :
To determine the value of \( x \) in the equation \(\frac{1}{5} x - \frac{2}{3} y = 30\) when \( y = 15 \), follow these steps:
1. Substitute \( y \) with 15 in the equation:
[tex]\[ \frac{1}{5} x - \frac{2}{3}(15) = 30 \][/tex]
2. Calculate \(\frac{2}{3}(15)\):
[tex]\[ \frac{2}{3} \times 15 = \frac{2 \times 15}{3} = \frac{30}{3} = 10 \][/tex]
Thus, the equation becomes:
[tex]\[ \frac{1}{5} x - 10 = 30 \][/tex]
3. Isolate \(\frac{1}{5} x\) by adding 10 to both sides:
[tex]\[ \frac{1}{5} x = 30 + 10 \][/tex]
[tex]\[ \frac{1}{5} x = 40 \][/tex]
4. Solve for \( x \) by multiplying both sides by 5:
[tex]\[ x = 40 \times 5 \][/tex]
[tex]\[ x = 200 \][/tex]
So, the value of [tex]\( x \)[/tex] when [tex]\( y = 15 \)[/tex] is [tex]\(\boxed{200}\)[/tex].
1. Substitute \( y \) with 15 in the equation:
[tex]\[ \frac{1}{5} x - \frac{2}{3}(15) = 30 \][/tex]
2. Calculate \(\frac{2}{3}(15)\):
[tex]\[ \frac{2}{3} \times 15 = \frac{2 \times 15}{3} = \frac{30}{3} = 10 \][/tex]
Thus, the equation becomes:
[tex]\[ \frac{1}{5} x - 10 = 30 \][/tex]
3. Isolate \(\frac{1}{5} x\) by adding 10 to both sides:
[tex]\[ \frac{1}{5} x = 30 + 10 \][/tex]
[tex]\[ \frac{1}{5} x = 40 \][/tex]
4. Solve for \( x \) by multiplying both sides by 5:
[tex]\[ x = 40 \times 5 \][/tex]
[tex]\[ x = 200 \][/tex]
So, the value of [tex]\( x \)[/tex] when [tex]\( y = 15 \)[/tex] is [tex]\(\boxed{200}\)[/tex].
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