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Solve for [tex] x [/tex].

[tex]\[ 3x = 6x - 2 \][/tex]



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[tex]\[ 34 \div 7 = \text{ ? } \][/tex]

A. \(4 \, \text{r} \, 4\)

B. \(6 \, \text{r} \, 7\)

C. \(3 \, \text{r} \, 6\)

D. \(4 \, \text{r} \, 6\)

Response:

Sagot :

GinnyAnswer
Sure, let's work through this division problem step-by-step.

1. First we need to identify the numbers:
- Dividend: \(34\)
- Divisor: \(7\)

2. Determine how many times the divisor (7) can fit into the dividend (34) without exceeding it.
- Calculate \(34 \div 7\):
- \(7 \times 1 = 7\)
- \(7 \times 2 = 14\)
- \(7 \times 3 = 21\)
- \(7 \times 4 = 28\)
- \(7 \times 5 = 35\) (which is greater than 34, so we use the previous result)

The quotient is \(4\) because \(7\) fits into \(34\) four times.

3. Next, we calculate the remainder:
- Multiply the divisor by the quotient: \(7 \times 4 = 28\)
- Subtract this result from the dividend: \(34 - 28 = 6\)

Therefore, the remainder is \(6\).

4. So, the division of 34 by 7 yields a quotient and remainder:
- Quotient: \(4\)
- Remainder: \(6\)

Thus, \(34 \div 7\) equals \(4\) with a remainder of \(6\).

So, the correct answer is [tex]\( D. 4 \, r \, 6 \)[/tex].
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