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MathsWatch

HOMEWORK - Retrieval Practice (5Y): 4

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Find the \( n \)th term of this number sequence:

[tex]\[ 2, 4, 6, 8, \ldots \][/tex]

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Sagot :

To find the \( n \)th term of the number sequence \( 2, 4, 6, 8, \ldots \):

1. Identify the sequence type:
This is an arithmetic sequence because the difference between consecutive terms is constant.

2. Determine the first term \( a \) and the common difference \( d \):
- The first term \( a \) is \( 2 \).
- The common difference \( d \) is found by subtracting the first term from the second term: \( 4 - 2 = 2 \).

3. Write the formula for the \( n \)th term of an arithmetic sequence:
The general formula for the \( n \)th term \( a_n \) of an arithmetic sequence is:
[tex]\[ a_n = a + (n - 1)d \][/tex]
Here, \( a \) is the first term, \( d \) is the common difference, and \( n \) is the position of the term in the sequence.

4. Substitute the known values into the formula:
- First term \( a = 2 \)
- Common difference \( d = 2 \)
[tex]\[ a_n = 2 + (n - 1) \times 2 \][/tex]

5. Simplify the expression:
[tex]\[ a_n = 2 + 2n - 2 \][/tex]
[tex]\[ a_n = 2n \][/tex]

6. Conclusion:
The \( n \)th term of the sequence \( 2, 4, 6, 8, \ldots \) is:
[tex]\[ a_n = 2n \][/tex]

So, if for example you wanted to find the 5th term (\( n = 5 \)) of this sequence, you would calculate:
[tex]\[ a_5 = 2 \times 5 = 10 \][/tex]

The result is [tex]\( 10 \)[/tex].
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