To find the value of \(\sqrt{121} + \sqrt[3]{125}\), we can analyze and solve each part separately.
1. Finding the square root of 121:
- The square root of a number \(a\) is a value \(b\) such that \(b^2 = a\).
- Here, we need to find \(\sqrt{121}\).
Since \(11 \times 11 = 121\), we conclude that \(\sqrt{121} = 11\).
2. Finding the cube root of 125:
- The cube root of a number \(b\) is a value \(c\) such that \(c^3 = b\).
- Here, we need to find \(\sqrt[3]{125}\).
Since \(5 \times 5 \times 5 = 125\), we conclude that \(\sqrt[3]{125} = 5\).
3. Adding the results together:
- Now, we add the values obtained from the square root and the cube root calculations.
We have \(\sqrt{121} = 11\) and \(\sqrt[3]{125} = 5\).
Thus,
[tex]\[
\sqrt{121} + \sqrt[3]{125} = 11 + 5 = 16
\][/tex]
So, the value of [tex]\(\sqrt{121} + \sqrt[3]{125}\)[/tex] is [tex]\(16\)[/tex].
