Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
To determine which of the given equations is not a linear equation, we need to check if each equation can be written in the standard form of a linear equation. A linear equation involves variables (like \( x \) and \( y \)) raised only to the first power and does not include products of these variables or any non-linear functions like \(\sin(x)\) or \(\exp(y)\).
Let's examine each equation:
### Equation A: \(\frac{1}{2} x + 3 y = 2\)
Here, \(\frac{1}{2} x\) and \(3 y\) are both linear terms because each variable is raised to the power of 1. This is a standard form linear equation.
### Equation B: \(x^3 - 5 y^2 = 4\)
In this equation, \(x\) is raised to the power of 3 and \(y\) is raised to the power of 2. Both of these terms are non-linear because the variables \(x\) and \(y\) are not raised solely to the first power.
### Equation C: \(x = 2\)
This represents a vertical line, which is indeed a linear equation because it can be viewed as \(1 \cdot x + 0 \cdot y = 2\).
### Equation D: \(y = 4\)
Similarly, this represents a horizontal line, which is also a linear equation because it can be seen as \(0 \cdot x + 1 \cdot y = 4\).
From this analysis, we can clearly see that the equation which is not a linear equation is:
[tex]\[ B) x^3 - 5 y^2 = 4 \][/tex]
So, the answer is B.
Let's examine each equation:
### Equation A: \(\frac{1}{2} x + 3 y = 2\)
Here, \(\frac{1}{2} x\) and \(3 y\) are both linear terms because each variable is raised to the power of 1. This is a standard form linear equation.
### Equation B: \(x^3 - 5 y^2 = 4\)
In this equation, \(x\) is raised to the power of 3 and \(y\) is raised to the power of 2. Both of these terms are non-linear because the variables \(x\) and \(y\) are not raised solely to the first power.
### Equation C: \(x = 2\)
This represents a vertical line, which is indeed a linear equation because it can be viewed as \(1 \cdot x + 0 \cdot y = 2\).
### Equation D: \(y = 4\)
Similarly, this represents a horizontal line, which is also a linear equation because it can be seen as \(0 \cdot x + 1 \cdot y = 4\).
From this analysis, we can clearly see that the equation which is not a linear equation is:
[tex]\[ B) x^3 - 5 y^2 = 4 \][/tex]
So, the answer is B.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.