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What is the inverse of the function [tex]f(x)=\frac{1}{4} x - 12[/tex]?

A. [tex]h(x)=48 x - 4[/tex]
B. [tex]h(x)=48 x + 4[/tex]
C. [tex]h(x)=4 x - 48[/tex]
D. [tex]h(x)=4 x + 48[/tex]


Sagot :

To find the inverse of the function \( f(x) = \frac{1}{4} x - 12 \), we need to follow these steps:

1. Express \(y\) in terms of \(x\):
First, rewrite the function \(f(x)\) by replacing \(f(x)\) with \(y\):
[tex]\[ y = \frac{1}{4} x - 12 \][/tex]

2. Swap \(x\) and \(y\):
To find the inverse function, we swap \(x\) and \(y\):
[tex]\[ x = \frac{1}{4} y - 12 \][/tex]

3. Solve for \(y\):
We need to solve this equation for \(y\):

Multiply both sides by 4 to clear the fraction:
[tex]\[ 4x = y - 48 \][/tex]

Add 48 to both sides to solve for \(y\):
[tex]\[ y = 4x + 48 \][/tex]

So, the inverse function \( f^{-1}(x) \) is:
[tex]\[ f^{-1}(x) = 4x + 48 \][/tex]

Among the given options:

- \(h(x) = 48x - 4\)
- \(h(x) = 48x + 4\)
- \(h(x) = 4x - 48\)
- \(h(x) = 4x + 48\)

The correct inverse function is:
[tex]\[ \boxed{h(x) = 4x + 48} \][/tex]