gabrielcolon522005
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Type the correct answer in the box. Use numerals instead of words.

[tex]
\begin{array}{l}
-3n^2 + 147 = 0 \\
n = \pm \square
\end{array}
[/tex]

Sagot :

GinnyAnswer
Certainly! Let's solve the quadratic equation \(-3n^2 + 147 = 0\) step by step.

1. Start with the given equation:
[tex]\[ -3n^2 + 147 = 0 \][/tex]

2. Move 147 to the other side of the equation to isolate the quadratic term:
[tex]\[ -3n^2 = -147 \][/tex]

3. Divide both sides of the equation by -3 to solve for \(n^2\):
[tex]\[ n^2 = \frac{-147}{-3} \][/tex]
[tex]\[ n^2 = 49 \][/tex]

4. Take the square root of both sides to solve for \(n\):
[tex]\[ n = \pm \sqrt{49} \][/tex]

5. Calculate the square root of 49:
[tex]\[ n = \pm 7 \][/tex]

Therefore, the solutions are:
[tex]\[ n = \pm 7 \][/tex]

In the box, you should write:
[tex]\[ 7 \][/tex]
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.