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Sagot :
Sure! Let's organize the steps and provide the correct justifications for each step of the solution.
\begin{tabular}{|c|l|}
\hline
Step & Justification \\
\hline
[tex]$\frac{17}{3}-\frac{3}{4} x=\frac{1}{2} x+5$[/tex] & given \\
\hline
[tex]$\frac{17}{3}-\frac{3}{4} x-\frac{17}{3}=\frac{1}{2} x+5-\frac{17}{3}$[/tex] & subtraction property of equality \\
\hline
[tex]$-\frac{3}{4} x=\frac{1}{2} x-\frac{2}{3}$[/tex] & simplification \\
\hline
[tex]$-\frac{3}{4} x-\frac{1}{2} x=\frac{1}{2} x-\frac{2}{3}-\frac{1}{2} x$[/tex] & subtraction property of equality \\
\hline
[tex]$-\frac{5}{4} x=-\frac{2}{3}$[/tex] & simplification \\
\hline
[tex]$-\frac{5}{4} x \cdot -\frac{4}{5}=-\frac{2}{3} \cdot -\frac{4}{5}$[/tex] & multiplication property of equality \\
\hline
[tex]$x=\frac{8}{15}$[/tex] & simplification \\
\hline
\end{tabular}
This structure shows each step of the solution with the appropriate justification for each transformation.
\begin{tabular}{|c|l|}
\hline
Step & Justification \\
\hline
[tex]$\frac{17}{3}-\frac{3}{4} x=\frac{1}{2} x+5$[/tex] & given \\
\hline
[tex]$\frac{17}{3}-\frac{3}{4} x-\frac{17}{3}=\frac{1}{2} x+5-\frac{17}{3}$[/tex] & subtraction property of equality \\
\hline
[tex]$-\frac{3}{4} x=\frac{1}{2} x-\frac{2}{3}$[/tex] & simplification \\
\hline
[tex]$-\frac{3}{4} x-\frac{1}{2} x=\frac{1}{2} x-\frac{2}{3}-\frac{1}{2} x$[/tex] & subtraction property of equality \\
\hline
[tex]$-\frac{5}{4} x=-\frac{2}{3}$[/tex] & simplification \\
\hline
[tex]$-\frac{5}{4} x \cdot -\frac{4}{5}=-\frac{2}{3} \cdot -\frac{4}{5}$[/tex] & multiplication property of equality \\
\hline
[tex]$x=\frac{8}{15}$[/tex] & simplification \\
\hline
\end{tabular}
This structure shows each step of the solution with the appropriate justification for each transformation.
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