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What is the value of this expression when [tex]$c=-4[tex]$[/tex] and [tex]$[/tex]d=10$[/tex]?

[tex]\frac{1}{4}\left(c^3+d^2\right)[/tex]

A. 2
B. 9
C. 21
D. 41


Sagot :

To find the value of the expression \(\frac{1}{4}\left(c^3 + d^2\right)\) when \(c = -4\) and \(d = 10\), follow these steps:

1. Substitute the values of \(c\) and \(d\) into the expression:
[tex]\[ \frac{1}{4}\left((-4)^3 + 10^2\right) \][/tex]

2. Calculate \((-4)^3\):
[tex]\[ (-4)^3 = (-4) \times (-4) \times (-4) = -64 \][/tex]

3. Calculate \(10^2\):
[tex]\[ 10^2 = 10 \times 10 = 100 \][/tex]

4. Add these results together:
[tex]\[ (-64) + 100 = 36 \][/tex]

5. Multiply the sum by \(\frac{1}{4}\):
[tex]\[ \frac{1}{4} \times 36 = 9 \][/tex]

Therefore, the value of the expression \(\frac{1}{4}\left(c^3 + d^2\right)\) when \(c = -4\) and \(d = 10\) is \(9\).

Hence, the correct answer is [tex]\( \boxed{9} \)[/tex].