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Sagot :
To determine which of the given tables represents a linear function, we need to examine whether the differences between consecutive \( y \)-values are consistent, indicating a constant rate of change, or slope.
### Table 1:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & \frac{1}{2} \\ \hline 2 & 1 \\ \hline 3 & \frac{3}{2} \\ \hline 4 & 2 \\ \hline \end{array} \][/tex]
The \( y \)-values are \(\frac{1}{2}, 1, \frac{3}{2}, 2 \).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} 1 - \frac{1}{2} = \frac{1}{2} \\ \frac{3}{2} - 1 = \frac{1}{2} \\ 2 - \frac{3}{2} = \frac{1}{2} \\ \end{array} \][/tex]
The differences are constant (\(\frac{1}{2}\)), indicating that Table 1 represents a linear function.
### Table 2:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & \frac{1}{1} \\ \hline 2 & \frac{1}{2} \\ \hline 3 & \frac{1}{3} \\ \hline 4 & \frac{1}{4} \\ \hline \end{array} \][/tex]
The \( y \)-values are \(\frac{1}{1}, \frac{1}{2}, \frac{1}{3}, \frac{1}{4} \).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} \frac{1}{2} - 1 \neq \text{constant} \\ \frac{1}{3} - \frac{1}{2} \neq \text{constant} \\ \frac{1}{4} - \frac{1}{3} \neq \text{constant} \end{array} \][/tex]
The differences are not consistent, indicating that Table 2 does not represent a linear function.
### Table 3:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 7 \\ \hline 2 & 9 \\ \hline 3 & 13 \\ \hline 4 & 21 \\ \hline \end{array} \][/tex]
The \( y \)-values are \(7, 9, 13, 21\).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} 9 - 7 = 2 \\ 13 - 9 = 4 \\ 21 - 13 = 8 \end{array} \][/tex]
The differences are not constant, indicating that Table 3 does not represent a linear function.
### Table 4:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 0 \\ \hline 2 & 6 \\ \hline 3 & 16 \\ \hline 4 & 30 \\ \hline \end{array} \][/tex]
The \( y \)-values are \(0, 6, 16, 30\).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} 6 - 0 = 6 \\ 16 - 6 = 10 \\ 30 - 16 = 14 \end{array} \][/tex]
The differences are not constant, indicating that Table 4 does not represent a linear function.
### Conclusion:
Upon examining all the tables, Table 1 is the only one that has consistent differences between the \( y \)-values. Therefore, Table 1 represents a linear function.
Thus, the table that represents a linear function is:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & \frac{1}{2} \\ \hline 2 & 1 \\ \hline 3 & \frac{3}{2} \\ \hline 4 & 2 \\ \hline \end{array} \][/tex]
### Table 1:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & \frac{1}{2} \\ \hline 2 & 1 \\ \hline 3 & \frac{3}{2} \\ \hline 4 & 2 \\ \hline \end{array} \][/tex]
The \( y \)-values are \(\frac{1}{2}, 1, \frac{3}{2}, 2 \).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} 1 - \frac{1}{2} = \frac{1}{2} \\ \frac{3}{2} - 1 = \frac{1}{2} \\ 2 - \frac{3}{2} = \frac{1}{2} \\ \end{array} \][/tex]
The differences are constant (\(\frac{1}{2}\)), indicating that Table 1 represents a linear function.
### Table 2:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & \frac{1}{1} \\ \hline 2 & \frac{1}{2} \\ \hline 3 & \frac{1}{3} \\ \hline 4 & \frac{1}{4} \\ \hline \end{array} \][/tex]
The \( y \)-values are \(\frac{1}{1}, \frac{1}{2}, \frac{1}{3}, \frac{1}{4} \).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} \frac{1}{2} - 1 \neq \text{constant} \\ \frac{1}{3} - \frac{1}{2} \neq \text{constant} \\ \frac{1}{4} - \frac{1}{3} \neq \text{constant} \end{array} \][/tex]
The differences are not consistent, indicating that Table 2 does not represent a linear function.
### Table 3:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 7 \\ \hline 2 & 9 \\ \hline 3 & 13 \\ \hline 4 & 21 \\ \hline \end{array} \][/tex]
The \( y \)-values are \(7, 9, 13, 21\).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} 9 - 7 = 2 \\ 13 - 9 = 4 \\ 21 - 13 = 8 \end{array} \][/tex]
The differences are not constant, indicating that Table 3 does not represent a linear function.
### Table 4:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & 0 \\ \hline 2 & 6 \\ \hline 3 & 16 \\ \hline 4 & 30 \\ \hline \end{array} \][/tex]
The \( y \)-values are \(0, 6, 16, 30\).
Calculate the differences between consecutive \( y \)-values:
[tex]\[ \begin{array}{l} 6 - 0 = 6 \\ 16 - 6 = 10 \\ 30 - 16 = 14 \end{array} \][/tex]
The differences are not constant, indicating that Table 4 does not represent a linear function.
### Conclusion:
Upon examining all the tables, Table 1 is the only one that has consistent differences between the \( y \)-values. Therefore, Table 1 represents a linear function.
Thus, the table that represents a linear function is:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline 1 & \frac{1}{2} \\ \hline 2 & 1 \\ \hline 3 & \frac{3}{2} \\ \hline 4 & 2 \\ \hline \end{array} \][/tex]
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