Get reliable answers to your questions at Westonci.ca, where our knowledgeable community is always ready to help. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Let's examine both parts of the problem step-by-step:
### Part A: Analyzing the Price of Fuel A
The price \( f(x) \) of fuel A after \( x \) months is given by the function:
[tex]\[ f(x) = 2.15(0.98)^x \][/tex]
1. Determine if the price is increasing or decreasing:
- The function \( f(x) = 2.15(0.98)^x \) is in the form of an exponential decay function because the base of the exponent (0.98) is less than 1.
- This indicates that the price of fuel A is decreasing over time.
2. Find the rate of percentage decrease per month:
- In exponential decay functions of the form \( f(x) = a \cdot b^x \), where \( 0 < b < 1 \), the base \( b \) represents \( 1 - r \), where \( r \) is the rate of decrease.
- Here, \( b = 0.98 \), hence \( 1 - r = 0.98 \).
- Solving for \( r \), we get \( r = 1 - 0.98 = 0.02 \).
- Converting this to a percentage gives us a 2% decrease per month.
Therefore, the price of fuel A is decreasing by 2% per month.
### Part B: Analyzing the Price of Fuel B
The table below shows the price \( g(m) \) of fuel B after \( m \) months:
[tex]\[ \begin{array}{|c|c|c|c|c|} \hline m \text{ (number of months)} & 1 & 2 & 3 & 4 \\ \hline g(m) \text{ (price in dollars)} & 4.19 & 3.98 & 3.78 & 3.59 \\ \hline \end{array} \][/tex]
1. Calculate the percentage change in price for fuel B from month-to-month:
The percentage change from month \( m \) to month \( m+1 \) is calculated as:
[tex]\[ \text{Percentage change} = \left( \frac{g(m) - g(m+1)}{g(m)} \right) \times 100 \][/tex]
- From month 1 to month 2:
[tex]\[ \left( \frac{4.19 - 3.98}{4.19} \right) \times 100 = 5.0119\% \][/tex]
- From month 2 to month 3:
[tex]\[ \left( \frac{3.98 - 3.78}{3.98} \right) \times 100 = 5.0251\% \][/tex]
- From month 3 to month 4:
[tex]\[ \left( \frac{3.78 - 3.59}{3.78} \right) \times 100 = 5.0265\% \][/tex]
The percentage changes are approximately \( 5.0119\% \), \( 5.0251\% \), and \( 5.0265\% \).
2. Find the greatest percentage change:
- Among the calculated percentage changes, the greatest percentage change is \( 5.0265\% \), which occurred from month 3 to month 4.
### Comparisons and Conclusion:
- Fuel A: The price is decreasing steadily by \( 2\% \) per month.
- Fuel B: The price has recorded percentage changes of approximately \( 5.0119\% \), \( 5.0251\% \), and \( 5.0265\% \) over the previous months.
Conclusion: Fuel B has recorded a greater percentage change in price over the previous month compared to Fuel A. The maximum percentage change for Fuel B recorded is approximately 5.0265%, which is greater than the steady 2% decrease per month for Fuel A.
### Part A: Analyzing the Price of Fuel A
The price \( f(x) \) of fuel A after \( x \) months is given by the function:
[tex]\[ f(x) = 2.15(0.98)^x \][/tex]
1. Determine if the price is increasing or decreasing:
- The function \( f(x) = 2.15(0.98)^x \) is in the form of an exponential decay function because the base of the exponent (0.98) is less than 1.
- This indicates that the price of fuel A is decreasing over time.
2. Find the rate of percentage decrease per month:
- In exponential decay functions of the form \( f(x) = a \cdot b^x \), where \( 0 < b < 1 \), the base \( b \) represents \( 1 - r \), where \( r \) is the rate of decrease.
- Here, \( b = 0.98 \), hence \( 1 - r = 0.98 \).
- Solving for \( r \), we get \( r = 1 - 0.98 = 0.02 \).
- Converting this to a percentage gives us a 2% decrease per month.
Therefore, the price of fuel A is decreasing by 2% per month.
### Part B: Analyzing the Price of Fuel B
The table below shows the price \( g(m) \) of fuel B after \( m \) months:
[tex]\[ \begin{array}{|c|c|c|c|c|} \hline m \text{ (number of months)} & 1 & 2 & 3 & 4 \\ \hline g(m) \text{ (price in dollars)} & 4.19 & 3.98 & 3.78 & 3.59 \\ \hline \end{array} \][/tex]
1. Calculate the percentage change in price for fuel B from month-to-month:
The percentage change from month \( m \) to month \( m+1 \) is calculated as:
[tex]\[ \text{Percentage change} = \left( \frac{g(m) - g(m+1)}{g(m)} \right) \times 100 \][/tex]
- From month 1 to month 2:
[tex]\[ \left( \frac{4.19 - 3.98}{4.19} \right) \times 100 = 5.0119\% \][/tex]
- From month 2 to month 3:
[tex]\[ \left( \frac{3.98 - 3.78}{3.98} \right) \times 100 = 5.0251\% \][/tex]
- From month 3 to month 4:
[tex]\[ \left( \frac{3.78 - 3.59}{3.78} \right) \times 100 = 5.0265\% \][/tex]
The percentage changes are approximately \( 5.0119\% \), \( 5.0251\% \), and \( 5.0265\% \).
2. Find the greatest percentage change:
- Among the calculated percentage changes, the greatest percentage change is \( 5.0265\% \), which occurred from month 3 to month 4.
### Comparisons and Conclusion:
- Fuel A: The price is decreasing steadily by \( 2\% \) per month.
- Fuel B: The price has recorded percentage changes of approximately \( 5.0119\% \), \( 5.0251\% \), and \( 5.0265\% \) over the previous months.
Conclusion: Fuel B has recorded a greater percentage change in price over the previous month compared to Fuel A. The maximum percentage change for Fuel B recorded is approximately 5.0265%, which is greater than the steady 2% decrease per month for Fuel A.
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.