Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Let's graph the logarithmic function:
[tex]\[ g(x) = \frac{1}{4} \log_2(x-4) - 3 \][/tex]
### Step-by-Step Solution
1. Understand the function form:
- The function \( \log_2(x-4) \) implies a domain constraint: \( x - 4 > 0 \), or \( x > 4 \). This means the function is only defined for \( x > 4 \).
- The term \( \frac{1}{4} \) is a vertical compression factor.
- Subtracting 3 at the end translates the graph downward by 3 units.
2. Identify the asymptote:
- The function \( \log_2(x-4) \) has a vertical asymptote where the argument inside the logarithm equals zero, which is at \( x = 4 \).
3. Plot points:
- To gather specific points, choose \( x \)-values greater than 4.
- Let's pick \( x = 8 \) and \( x = 12 \).
4. Calculate \( y \)-values for these points:
- For \( x = 8 \):
[tex]\[ g(8) = \frac{1}{4} \log_2(8-4) - 3 = \frac{1}{4} \log_2(4) - 3 = \frac{1}{4} \cdot 2 - 3 = \frac{1}{2} - 3 = -2.5 \][/tex]
- For \( x = 12 \):
[tex]\[ g(12) = \frac{1}{4} \log_2(12-4) - 3 = \frac{1}{4} \log_2(8) - 3 = \frac{1}{4} \cdot 3 - 3 = \frac{3}{4} - 3 = -2.25 \][/tex]
5. Graph the function:
- Plot the points \( (8, -2.5) \) and \( (12, -2.25) \).
- Draw the vertical asymptote at \( x = 4 \).
### Plot Description:
- Vertical asymptote: Draw a dashed vertical line at \( x = 4 \).
- Points:
- \( (8, -2.5) \) - Plot this point and label it.
- \( (12, -2.25) \) - Plot this point and label it.
- Draw the curve: Sketch the curve starting just to the right of \( x = 4 \) and passing through the plotted points. The curve should approach but never intersect the line \( x = 4 \), and continue to decrease slowly as \( x \) increases.
### Final Graph
The graph displays a logarithmic curve that becomes steeper as x approaches 4 from the right and flattens out as x increases. The curve passes through the points (8, -2.5) and (12, -2.25), with a vertical asymptote at \( x = 4 \).
By following these steps, you can graph the logarithmic function [tex]\( g(x) = \frac{1}{4} \log_2(x-4) - 3 \)[/tex], plot two meaningful points on it, and highlight the asymptote.
[tex]\[ g(x) = \frac{1}{4} \log_2(x-4) - 3 \][/tex]
### Step-by-Step Solution
1. Understand the function form:
- The function \( \log_2(x-4) \) implies a domain constraint: \( x - 4 > 0 \), or \( x > 4 \). This means the function is only defined for \( x > 4 \).
- The term \( \frac{1}{4} \) is a vertical compression factor.
- Subtracting 3 at the end translates the graph downward by 3 units.
2. Identify the asymptote:
- The function \( \log_2(x-4) \) has a vertical asymptote where the argument inside the logarithm equals zero, which is at \( x = 4 \).
3. Plot points:
- To gather specific points, choose \( x \)-values greater than 4.
- Let's pick \( x = 8 \) and \( x = 12 \).
4. Calculate \( y \)-values for these points:
- For \( x = 8 \):
[tex]\[ g(8) = \frac{1}{4} \log_2(8-4) - 3 = \frac{1}{4} \log_2(4) - 3 = \frac{1}{4} \cdot 2 - 3 = \frac{1}{2} - 3 = -2.5 \][/tex]
- For \( x = 12 \):
[tex]\[ g(12) = \frac{1}{4} \log_2(12-4) - 3 = \frac{1}{4} \log_2(8) - 3 = \frac{1}{4} \cdot 3 - 3 = \frac{3}{4} - 3 = -2.25 \][/tex]
5. Graph the function:
- Plot the points \( (8, -2.5) \) and \( (12, -2.25) \).
- Draw the vertical asymptote at \( x = 4 \).
### Plot Description:
- Vertical asymptote: Draw a dashed vertical line at \( x = 4 \).
- Points:
- \( (8, -2.5) \) - Plot this point and label it.
- \( (12, -2.25) \) - Plot this point and label it.
- Draw the curve: Sketch the curve starting just to the right of \( x = 4 \) and passing through the plotted points. The curve should approach but never intersect the line \( x = 4 \), and continue to decrease slowly as \( x \) increases.
### Final Graph
The graph displays a logarithmic curve that becomes steeper as x approaches 4 from the right and flattens out as x increases. The curve passes through the points (8, -2.5) and (12, -2.25), with a vertical asymptote at \( x = 4 \).
By following these steps, you can graph the logarithmic function [tex]\( g(x) = \frac{1}{4} \log_2(x-4) - 3 \)[/tex], plot two meaningful points on it, and highlight the asymptote.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.