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Find all values of [tex]\theta[/tex], where [tex]0^{\circ} \leq \theta \leq 360^{\circ}[/tex], when [tex]\cos \theta = -\frac{\sqrt{3}}{2}[/tex].

Enter your answers in increasing order.

[tex]\[
\begin{array}{l}
\theta = 150^\circ \\
\theta = 210^\circ
\end{array}
\][/tex]

Sagot :

To find the values of \(\theta\) where \(0^{\circ} \leq \theta \leq 360^{\circ}\) and \(\cos \theta = -\frac{\sqrt{3}}{2}\), we can follow these steps:

1. Identify the cosine value:
[tex]\[ \cos \theta = -\frac{\sqrt{3}}{2} \][/tex]

2. Understand the key angles where cosine takes on specific values:
[tex]\[ \cos(\theta) = -\frac{\sqrt{3}}{2} \][/tex]
The reference angle for \(\frac{\sqrt{3}}{2}\) is \(30^{\circ}\) because \(\cos(30^{\circ}) = \frac{\sqrt{3}}{2}\).

3. Since the cosine function is negative, consider in which quadrants the cosine function is negative:
- Cosine is negative in the second and third quadrants.

4. Calculate the angles in these quadrants given that the reference angle is \(30^{\circ}\):

- In the second quadrant, the angle is found by subtracting the reference angle from \(180^{\circ}\):
[tex]\[ 180^{\circ} - 30^{\circ} = 150^{\circ} \][/tex]

- In the third quadrant, the angle is found by adding the reference angle to \(180^{\circ}\):
[tex]\[ 180^{\circ} + 30^{\circ} = 210^{\circ} \][/tex]

Therefore, the angles where \(\cos \theta = -\frac{\sqrt{3}}{2}\) and \(0^{\circ} \leq \theta \leq 360^{\circ}\) are:
[tex]\[ \theta = 150^{\circ} \quad \text{and} \quad \theta = 210^{\circ} \][/tex]

We can write our final answers in increasing order as:
[tex]\[ \begin{array}{ll} \theta = 150^{\circ} \\ \theta = 210^{\circ} \end{array} \][/tex]
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