mayaapple20
Answered

Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

\begin{tabular}{|c|c|c|c|c|}
\cline{2-5} \multicolumn{1}{c|}{} & [tex]$A$[/tex] & [tex]$B$[/tex] & [tex]$C$[/tex] & Total \\
\hline [tex]$D$[/tex] & 0.12 & 0.78 & 0.10 & 1.0 \\
\hline [tex]$E$[/tex] & [tex]$R$[/tex] & [tex]$S$[/tex] & [tex]$T$[/tex] & 1.0 \\
\hline Total & [tex]$U$[/tex] & [tex]$X$[/tex] & [tex]$Y$[/tex] & 1.0 \\
\hline
\end{tabular}

Which value for [tex]$R$[/tex] in the table would most likely indicate an association between the conditional variables?

A. 0.09
B. 0.10
C. 0.13
D. 0.79

Sagot :

GinnyAnswer
To determine the value of \( R \) that most likely indicates an association between the conditional variables, let's perform a detailed analysis.

We are given the following table:

[tex]\[ \begin{tabular}{|c|c|c|c|c|} \cline { 2 - 5 } \multicolumn{1}{c|}{} & A & B & C & Total \\ \hline D & 0.12 & 0.78 & 0.10 & 1.0 \\ \hline E & R & S & T & 1.0 \\ \hline Total & U & X & Y & 1.0 \\ \hline \end{tabular} \][/tex]

From the data provided:
- The totals for each column (A, B, and C) add up to the overall total of 1.0.
- The total of row D is 1.0.
- The total of row E is also 1.0, which means:

[tex]\[ R + S + T = 1.0 \][/tex]

### Step-by-Step Solution

#### Step 1: Identify values for A, B, and C
Each entry in the D row must sum up to 1.0:
- \( A_D = 0.12 \)
- \( A_B = 0.78 \)
- \( A_C = 0.10 \)

#### Step 2: Calculate \( R \)
We need to calculate the left-over value \( R \).

[tex]\[ A_D + A_B + A_C = 0.12 + 0.78 + 0.10 = 1.0 \][/tex]

Since \( A_D, A_B, \) and \( A_C \) together already sum to 1.0 under row D, the sum of row E \( (R, S, T) \) should individually make up 1.0:

Let’s look at the possible values of \( R \):

- If \( R = 0.09 \):
[tex]\[ R + S + T = 0.09 + S + T = 1.0 \][/tex]
[tex]\[ S + T = 0.91 \][/tex]
- If \( R = 0.10 \):
[tex]\[ R + S + T = 0.10 + S + T = 1.0 \][/tex]
[tex]\[ S + T = 0.90 \][/tex]
- If \( R = 0.13 \):
[tex]\[ R + S + T = 0.13 + S + T = 1.0 \][/tex]
[tex]\[ S + T = 0.87 \][/tex]
- If \( R = 0.79 \):
[tex]\[ R + S + T = 0.79 + S + T = 1.0 \][/tex]
[tex]\[ S + T = 0.21 \][/tex]

#### Step 3: Choose the value of \( R \) that shows a likely natural distribution
Since values for \( S \) and \( T \) need to sum to a much more naturally balanced distribution, let’s analyze according to the mixing of higher interdependencies:

Considering our odd distributions for the plausible values:
- \( R = 0.79 \) leaves \( S \) and \( T \) very low combined \( 0.21 \).

Detailly, \( R = 0.09, 0.10, 0.13 \) leaves the remainder of \( S \) and \( T \):
- Hence \( R = 0.09, 0.13 \) is more equally probable.

Thus, a normalized association highly advises \( R = 0.13 \).

### Conclusion

[tex]\( R = 0.13 \)[/tex] is the valuable distributional figure that seems explainably natural, showing an association amongst the variables.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.