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Write an equation in slope-intercept form for the line with slope [tex]\frac{2}{5}[/tex] and [tex]y[/tex]-intercept -1.

[tex]y = \frac{2}{5}x - 1[/tex]


Sagot :

To write the equation of a line in slope-intercept form, we use the formula:

[tex]\[ y = mx + b \][/tex]

where \( m \) represents the slope and \( b \) represents the y-intercept.

1. Identify the slope:
Given the slope \( m \) is \(\frac{2}{5}\).

2. Identify the y-intercept:
Given the y-intercept \( b \) is \(-1\).

3. Substitute the values into the slope-intercept form:
Substitute \( m = \frac{2}{5} \) and \( b = -1 \) into the equation \( y = mx + b \).

Thus, the equation of the line is:

[tex]\[ y = \frac{2}{5}x - 1 \][/tex]

To convert the fraction \( \frac{2}{5} \) to a decimal, we calculate \( \frac{2}{5} = 0.4 \).

Therefore, the equation in decimal form is:

[tex]\[ y = 0.4x - 1 \][/tex]

So, the final equation of the line is:

[tex]\[ y = 0.4x - 1 \][/tex]