To determine which substance will be produced at a faster rate in the given chemical reaction:
[tex]\[
C_3H_8 + 5 O_2 \rightarrow 3 CO_2 + 4 H_2O
\][/tex]
we need to look at the coefficients of the products (CO₂ and H₂O) in the balanced chemical equation.
### Step-by-Step Analysis:
1. Identify the Reactants and Products:
- Reactants: \(C_3H_8\) and \(O_2\)
- Products: \(CO_2\) and \(H_2O\)
2. Write Down the Balanced Equation:
[tex]\[
C_3H_8 + 5 O_2 \rightarrow 3 CO_2 + 4 H_2O
\][/tex]
3. Observe the Coefficients of the Products:
- For \(CO_2\), the coefficient is 3.
- For \(H_2O\), the coefficient is 4.
4. Compare the Coefficients:
- The coefficient for \(H_2O\) (4) is greater than the coefficient for \(CO_2\) (3).
### Conclusion:
Since the coefficient of \(H_2O\) is larger than that of \(CO_2\), \(H_2O\) will be produced at a faster rate than \(CO_2\).
So, the substance that will be produced at a faster rate is:
[tex]\[
\boxed{H_2O}
\][/tex]
